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Activity 2.7.1 Linear Inequality Notation Matching Game

[latex](-6,2)[/latex]
[latex](-5,1\rbrack[/latex]
[latex]\lbrack1,8)[/latex]
[latex](-\infty,-6)\;\cup\;(2,\infty)[/latex]
[latex]\{x\vert x>5\;and\; x\leq1\}[/latex]
[latex]\{x\vert x>-6\;and\;x
[latex]\{x\vert x\leq-4\;or\;x>2\}[/latex]
[latex](-\infty,-4\rbrack\;\cup\;(2,\infty)[/latex]
[latex]\lbrack1,4)[/latex]
[latex](6,\infty)[/latex]
[latex]x\leq-6\;or\;x>2[/latex]
[latex]x\geq1\;and\;x
[latex]x>-5\;and\;x\leq1[/latex]
[latex]x(2,6)[/latex]
[latex]x>2\;and\;x
[latex]x>6[/latex]
[latex](6,-6)[/latex]
[latex]\{x\vert x\geq1\;and\;x

Why is there a closing p tag? [latex]\{x\vert x>-6\;and\;x<6)[/latex]</p>

Why is there a closing p tag? [latex]x\geq1\;and\;x<8[/latex]</p>

Why is there a closing p tag? [latex]x>2\;and\;x<6[/latex]</p>

Why is there a closing p tag? [latex]\{x\vert x\geq1\;and\;x<4\}[/latex]</p>

The LaTeX renders fine: [latex]\{x\vert x>-6\;and\;x<6)[/latex] LaTeX renders fine: [latex]x\geq1\;and\;x<8[/latex] LaTeX renders fine: [latex]x>2\;and\;x<6[/latex] LaTeX renders fine: [latex]\{x\vert x\geq1\;and\;x<4\}[/latex] like</p>

This is My First Attempt

[latex](-6,2)[/latex]
[latex]\lbrack1,8)[/latex]
[latex]\{x\vert x>5\;and\; x\leq1\}[/latex]
[latex]\{x\vert x\leq-4\;or\;x>2\}[/latex]
[latex]\lbrack1,4)[/latex]
[latex]x\leq-6\;or\;x>2[/latex]
[latex]x>-5\;and\;x\leq1[/latex]
[latex]x>2\;and\;x
[latex](-5,1/rbrack[/latex]
[latex](-\infty,-6)\;\cup\;(2,\infty)[/latex]
[latex]\{x\vert x>-6\;and\;x<6)[/latex] [latex](-\infty,-4\rbrack\;\cup\;(2,\infty)[/latex] [latex](6,\infty)[/latex] [latex]x\geq1\;and\;x<8[/latex] [latex]x(2,6)[/latex] [latex]x>6[/latex]
[latex]\{x\vertx\geq1\;and\;x

Activity 2.7.2 Solving Absolute Value Inequalities Solve the absolute value inequality, graph the solution on the number line and write solution in interval notation. [latex]|c|-3\leq0[/latex]
 
[latex]|\frac{n}{4}|\leq3[/latex]
 
[latex]|-9p|\leq54[/latex]
 
[latex]|q|-3>-2[/latex]
 
[latex]|10+4x|<14[/latex]   [latex]-|\frac{x-4}{5}|\geq2[/latex]   [latex]2|x|+14>32[/latex]
 
[latex]\frac{|3+r}{7}\leq5[/latex]
 
[latex]|b-8|+10>22[/latex]
 
[latex]|\frac{x}{6}|\geq5[/latex]

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