{"id":29,"date":"2019-08-20T17:01:17","date_gmt":"2019-08-20T21:01:17","guid":{"rendered":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/chapter\/factoring-polynomials\/"},"modified":"2022-06-01T10:39:17","modified_gmt":"2022-06-01T14:39:17","slug":"factoring-polynomials","status":"publish","type":"chapter","link":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/chapter\/factoring-polynomials\/","title":{"raw":"Factoring Polynomials","rendered":"Factoring Polynomials"},"content":{"raw":"<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\nIn this section students will:\n<ul>\n \t<li>Factor the greatest common factor of a polynomial.<\/li>\n \t<li>Factor a trinomial.<\/li>\n \t<li>Factor by grouping.<\/li>\n \t<li>Factor a perfect square trinomial.<\/li>\n \t<li>Factor a difference of squares.<\/li>\n \t<li>Factor the sum and difference of cubes.<\/li>\n \t<li>Factor expressions using fractional or negative exponents.<\/li>\n<\/ul>\n<\/div>\n<p id=\"fs-id1167339261641\">Imagine that we are trying to find the area of a lawn so that we can determine how much grass seed to purchase. The lawn is the green portion in <a class=\"autogenerated-content\" href=\"#Figure_01_05_001\">(Figure)<\/a>.<\/p>\n\n<div id=\"Figure_01_05_001\" class=\"small wp-caption aligncenter\">\n\n[caption id=\"\" align=\"aligncenter\" width=\"487\" class=\"small\"]<img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3252\/2018\/07\/19132149\/CNX_CAT_Figure_01_05_001.jpg\" alt=\"A large rectangle with smaller squares and a rectangle inside. The length of the outer rectangle is 6x and the width is 10x. The side length of the squares is 4 and the height of the width of the inner rectangle is 4.\" width=\"487\" height=\"259\"> <strong>Figure 1.<\/strong>[\/caption]\n\n<\/div>\n<p id=\"fs-id1167339156365\">The area of the entire region can be found using the formula for the area of a rectangle.<\/p>\n\n<div id=\"fs-id1167339219134\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{ccc}\\hfill A&amp; =&amp; lw\\hfill \\\\ &amp; =&amp; 10x\\cdot 6x\\hfill \\\\ &amp; =&amp; 60{x}^{2}{\\text{ units}}^{2}\\hfill \\end{array}[\/latex]<\/div>\n<p id=\"fs-id1167339216289\">The areas of the portions that do not require grass seed need to be subtracted from the area of the entire region. The two square regions each have an area of[latex]\\,A={s}^{2}={4}^{2}=16\\,[\/latex]units<sup>2<\/sup>. The other rectangular region has one side of length[latex]\\,10x-8\\,[\/latex]and one side of length[latex]\\,4,[\/latex]giving an area of[latex]\\,A=lw=4\\left(10x-8\\right)=40x-32\\,[\/latex]units<sup>2<\/sup>. So the region that must be subtracted has an area of[latex]\\,2\\left(16\\right)+40x-32=40x\\,[\/latex]units<sup>2<\/sup>.<\/p>\n<p id=\"fs-id1167339224267\">The area of the region that requires grass seed is found by subtracting[latex]\\,60{x}^{2}-40x\\,[\/latex]units<sup>2<\/sup>. This area can also be expressed in factored form as[latex]\\,20x\\left(3x-2\\right)\\,[\/latex]units<sup>2<\/sup>. We can confirm that this is an equivalent expression by multiplying.<\/p>\n<p id=\"fs-id1167339243193\">Many polynomial expressions can be written in simpler forms by factoring. In this section, we will look at a variety of methods that can be used to factor polynomial expressions.<\/p>\n\n<div id=\"fs-id1167339224262\" class=\"bc-section section\">\n<h3>Factoring the Greatest Common Factor of a Polynomial<\/h3>\n<p id=\"fs-id1167339226451\">When we study fractions, we learn that the greatest common factor (GCF) of two numbers is the largest number that divides evenly into both numbers. For instance,[latex]\\,4\\,[\/latex]is the GCF of[latex]\\,16\\,[\/latex]and[latex]\\,20\\,[\/latex]because it is the largest number that divides evenly into both[latex]\\,16\\,[\/latex]and[latex]\\,20\\,[\/latex]The GCF of polynomials works the same way:[latex]\\,4x\\,[\/latex]is the GCF of[latex]\\,16x\\,[\/latex]and[latex]\\,20{x}^{2}\\,[\/latex]because it is the largest polynomial that divides evenly into both[latex]\\,16x\\,[\/latex]and[latex]\\,20{x}^{2}.[\/latex]<\/p>\n<p id=\"fs-id1167339171909\">When factoring a polynomial expression, our first step should be to check for a GCF. Look for the GCF of the coefficients, and then look for the GCF of the variables.<\/p>\n\n<div id=\"fs-id1167339144723\" class=\"textbox key-takeaways\">\n<h3>Greatest Common Factor<\/h3>\n<p id=\"fs-id1167339150653\">The greatest common factor (GCF) of polynomials is the largest polynomial that divides evenly into the polynomials.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339220518\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339145267\"><strong>Given a polynomial expression, factor out the greatest common factor.\n<\/strong><\/p>\n\n<ol id=\"fs-id1167339147626\" type=\"1\">\n \t<li>Identify the GCF of the coefficients.<\/li>\n \t<li>Identify the GCF of the variables.<\/li>\n \t<li>Combine to find the GCF of the expression.<\/li>\n \t<li>Determine what the GCF needs to be multiplied by to obtain each term in the expression.<\/li>\n \t<li>Write the factored expression as the product of the GCF and the sum of the terms we need to multiply by.<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_01\" class=\"textbox examples\">\n<div id=\"fs-id1167339243738\">\n<div id=\"fs-id1167339156623\">\n<h3>Factoring the Greatest Common Factor<\/h3>\n<p id=\"fs-id1167339318400\">Factor[latex]\\,6{x}^{3}{y}^{3}+45{x}^{2}{y}^{2}+21xy.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339167326\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339167326\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339167326\"]\n<p id=\"fs-id1167339212882\">First, find the GCF of the expression. The GCF of[latex]\\,6,45,[\/latex]and[latex]\\,21\\,[\/latex]is[latex]\\,3.\\,[\/latex]The GCF of[latex]\\,{x}^{3},{x}^{2},[\/latex]and[latex]\\,x\\,[\/latex]is[latex]\\,x.\\,[\/latex](Note that the GCF of a set of expressions in the form[latex]\\,{x}^{n}\\,[\/latex]will always be the exponent of lowest degree.) And the GCF of[latex]\\,{y}^{3},{y}^{2},[\/latex]and[latex]\\,y\\,[\/latex]is[latex]\\,y.\\,[\/latex]Combine these to find the GCF of the polynomial,[latex]\\,3xy.[\/latex]<\/p>\n<p id=\"fs-id1167339212530\">Next, determine what the GCF needs to be multiplied by to obtain each term of the polynomial. We find that[latex]\\,3xy\\left(2{x}^{2}{y}^{2}\\right)=6{x}^{3}{y}^{3},3xy\\left(15xy\\right)=45{x}^{2}{y}^{2},[\/latex]and[latex]\\,3xy\\left(7\\right)=21xy.[\/latex]<\/p>\n<p id=\"fs-id1167339330136\">Finally, write the factored expression as the product of the GCF and the sum of the terms we needed to multiply by.<\/p>\n\n<div id=\"fs-id1167339186024\" class=\"unnumbered aligncenter\">[latex]\\left(3xy\\right)\\left(2{x}^{2}{y}^{2}+15xy+7\\right)[\/latex][\/hidden-answer]<\/div>\n<\/div>\n<div id=\"fs-id1167339276172\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339136986\">After factoring, we can check our work by multiplying. Use the distributive property to confirm that[latex]\\,\\left(3xy\\right)\\left(2{x}^{2}{y}^{2}+15xy+7\\right)=6{x}^{3}{y}^{3}+45{x}^{2}{y}^{2}+21xy.[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339144942\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_01\">\n<div id=\"fs-id1167339344600\">\n<p id=\"fs-id1167339344602\">Factor[latex]\\,x\\left({b}^{2}-a\\right)+6\\left({b}^{2}-a\\right)\\,[\/latex]by pulling out the GCF.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339152770\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339152770\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339152770\"]\n<p id=\"fs-id1167339152771\">[latex]\\left({b}^{2}-a\\right)\\left(x+6\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339432992\" class=\"bc-section section\">\n<h3>Factoring a Trinomial with Leading Coefficient 1<\/h3>\n<p id=\"fs-id1167339432966\">Although we should always begin by looking for a GCF, pulling out the GCF is not the only way that polynomial expressions can be factored. The polynomial[latex]\\,{x}^{2}+5x+6\\,[\/latex]has a GCF of 1, but it can be written as the product of the factors[latex]\\,\\left(x+2\\right)\\,[\/latex]and[latex]\\,\\left(x+3\\right).[\/latex]<\/p>\n<p id=\"fs-id1167339318134\">Trinomials of the form[latex]\\,{x}^{2}+bx+c\\,[\/latex]can be factored by finding two numbers with a product of[latex]c\\,[\/latex]and a sum of[latex]\\,b.\\,[\/latex]The trinomial[latex]\\,{x}^{2}+10x+16,[\/latex]for example, can be factored using the numbers[latex]\\,2\\,[\/latex]and[latex]\\,8\\,[\/latex]because the product of those numbers is[latex]\\,16\\,[\/latex]and their sum is[latex]\\,10.\\,[\/latex]The trinomial can be rewritten as the product of[latex]\\,\\left(x+2\\right)\\,[\/latex]and[latex]\\,\\left(x+8\\right).[\/latex]<\/p>\n\n<div id=\"fs-id1167339149443\" class=\"textbox key-takeaways\">\n<h3>Factoring a Trinomial with Leading Coefficient 1<\/h3>\n<p id=\"fs-id1167339176943\">A trinomial of the form[latex]\\,{x}^{2}+bx+c\\,[\/latex]can be written in factored form as[latex]\\,\\left(x+p\\right)\\left(x+q\\right)\\,[\/latex]where[latex]\\,pq=c\\,[\/latex]and[latex]\\,p+q=b.[\/latex]<\/p>\n\n<\/div>\n<div class=\"precalculus qa textbox shaded\">\n<p id=\"fs-id1167339329107\"><strong>Can every trinomial be factored as a product of binomials?<\/strong><\/p>\n<p id=\"fs-id1167339433613\"><em>No. Some polynomials cannot be factored. These polynomials are said to be prime.<\/em><\/p>\n\n<\/div>\n<div id=\"fs-id1167339157766\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339231645\"><strong>Given a trinomial in the form[latex]\\,{x}^{2}+bx+c,[\/latex]factor it.<\/strong><\/p>\n\n<ol id=\"fs-id1167339151903\" type=\"1\">\n \t<li>List factors of[latex]\\,c.[\/latex]<\/li>\n \t<li>Find[latex]\\,p\\,[\/latex]and[latex]\\,q,[\/latex]a pair of factors of[latex]\\,c\\,[\/latex]with a sum of[latex]\\,b.[\/latex]<\/li>\n \t<li>Write the factored expression[latex]\\,\\left(x+p\\right)\\left(x+q\\right).[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_02\" class=\"textbox examples\">\n<div id=\"fs-id1167339139078\">\n<div id=\"fs-id1167339185064\">\n<h3>Factoring a Trinomial with Leading Coefficient 1<\/h3>\n<p id=\"fs-id1167339185070\">Factor[latex]\\,{x}^{2}+2x-15.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339281370\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339281370\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339281370\"]\n<p id=\"fs-id1167339281372\">We have a trinomial with leading coefficient[latex]\\,1,b=2,[\/latex]and[latex]\\,c=-15.\\,[\/latex]We need to find two numbers with a product of[latex]\\,-15\\,[\/latex]and a sum of[latex]\\,2.\\,[\/latex]In <a class=\"autogenerated-content\" href=\"#Table_01_05_01\">(Figure)<\/a>, we list factors until we find a pair with the desired sum.<\/p>\n\n<table id=\"Table_01_05_01\" summary=\"A table with five rows and two columns. The first row has columns labeled: Factors of -15 and Sum of Factors. The entries in the first column are: 1, -15; -1, 15; 3, -5; and -3,5. The entries in the second column are: -14, 14, -2, and 2.\"><caption>&nbsp;<\/caption>\n<thead>\n<tr>\n<th>Factors of[latex]\\,-15[\/latex]<\/th>\n<th>Sum of Factors<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]1,-15[\/latex]<\/td>\n<td>[latex]-14[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-1,15[\/latex]<\/td>\n<td>14<\/td>\n<\/tr>\n<tr>\n<td>[latex]3,-5[\/latex]<\/td>\n<td>[latex]-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-3,5[\/latex]<\/td>\n<td>2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-id1167339137924\">Now that we have identified[latex]\\,p\\,[\/latex]and[latex]\\,q\\,[\/latex]as[latex]\\,-3\\,[\/latex]and[latex]\\,5,[\/latex]write the factored form as[latex]\\,\\left(x-3\\right)\\left(x+5\\right).[\/latex][\/hidden-answer]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339168604\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339290229\">We can check our work by multiplying. Use FOIL to confirm that[latex]\\,\\left(x-3\\right)\\left(x+5\\right)={x}^{2}+2x-15.[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339328852\" class=\"precalculus qa textbox shaded\">\n<p id=\"fs-id1167339243866\"><strong>Does the order of the factors matter?<\/strong><\/p>\n<p id=\"fs-id1167339243870\"><em>No. Multiplication is commutative, so the order of the factors does not matter.<\/em><\/p>\n\n<\/div>\n<div id=\"fs-id1167339261843\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_02\">\n<div id=\"fs-id1167339155364\">\n<p id=\"fs-id1167339155365\">Factor[latex]\\,{x}^{2}-7x+6.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339429921\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339429921\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339429921\"]\n<p id=\"fs-id1167339429922\">[latex]\\left(x-6\\right)\\left(x-1\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339220936\" class=\"bc-section section\">\n<h3>Factoring by Grouping<\/h3>\n<p id=\"fs-id1167339328929\">Trinomials with leading coefficients other than 1 are slightly more complicated to factor. For these trinomials, we can factor by grouping by dividing the <em>x<\/em> term into the sum of two terms, factoring each portion of the expression separately, and then factoring out the GCF of the entire expression. The trinomial[latex]\\,2{x}^{2}+5x+3\\,[\/latex]can be rewritten as[latex]\\,\\left(2x+3\\right)\\left(x+1\\right)\\,[\/latex]using this process. We begin by rewriting the original expression as[latex]\\,2{x}^{2}+2x+3x+3\\,[\/latex]and then factor each portion of the expression to obtain[latex]\\,2x\\left(x+1\\right)+3\\left(x+1\\right).\\,[\/latex]We then pull out the GCF of[latex]\\,\\left(x+1\\right)\\,[\/latex]to find the factored expression.<\/p>\n\n<div id=\"fs-id1167339324878\" class=\"textbox key-takeaways\">\n<h3>Factor by Grouping<\/h3>\n<p id=\"fs-id1167339218884\">To factor a trinomial in the form[latex]\\,a{x}^{2}+bx+c\\,[\/latex]by grouping, we find two numbers with a product of[latex]\\,ac\\,[\/latex]and a sum of[latex]\\,b.\\,[\/latex]We use these numbers to divide the[latex]\\,x\\,[\/latex]term into the sum of two terms and factor each portion of the expression separately, then factor out the GCF of the entire expression.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339318193\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<strong>Given a trinomial in the form[latex]\\,a{x}^{2}+bx+c,[\/latex]factor by grouping.<\/strong>\n<ol id=\"fs-id1167339197004\" type=\"1\">\n \t<li>List factors of[latex]\\,ac.[\/latex]<\/li>\n \t<li>Find[latex]\\,p\\,[\/latex]and[latex]\\,q,[\/latex]a pair of factors of[latex]\\,ac\\,[\/latex]with a sum of[latex]\\,b.[\/latex]<\/li>\n \t<li>Rewrite the original expression as[latex]\\,a{x}^{2}+px+qx+c.[\/latex]<\/li>\n \t<li>Pull out the GCF of[latex]\\,a{x}^{2}+px.[\/latex]<\/li>\n \t<li>Pull out the GCF of[latex]\\,qx+c.[\/latex]<\/li>\n \t<li>Factor out the GCF of the expression.<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_03\" class=\"textbox examples\">\n<div id=\"fs-id1167339139430\">\n<div id=\"fs-id1167339139433\">\n<h3>Factoring a Trinomial by Grouping<\/h3>\n<p id=\"fs-id1167339260387\">Factor[latex]\\,5{x}^{2}+7x-6\\,[\/latex]by grouping.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339176878\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339176878\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339176878\"]\n<p id=\"fs-id1167339176880\">We have a trinomial with[latex]\\,a=5,b=7,[\/latex]and[latex]\\,c=-6.\\,[\/latex]First, determine[latex]\\,ac=-30.\\,[\/latex]We need to find two numbers with a product of[latex]\\,-30\\,[\/latex]and a sum of[latex]\\,7.\\,[\/latex]In <a class=\"autogenerated-content\" href=\"#Table_01_05_02\">(Figure)<\/a>, we list factors until we find a pair with the desired sum.<\/p>\n\n<table id=\"Table_01_05_02\" summary=\"A table with 7 rows and 2 columns. The first column is labeled: Factors of -30 while the second is labeled: Sum of Factors. The entries in the first column are: 1, -30; -1, 30; 2, -15; -2, 15; 3, -10; and -3, 10. The entries in the second column are: -29, 29, -13, 13, -7, and 7.\"><caption>&nbsp;<\/caption>\n<thead>\n<tr>\n<th>Factors of[latex]\\,-30[\/latex]<\/th>\n<th>Sum of Factors<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]1,-30[\/latex]<\/td>\n<td>[latex]-29[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-1,30[\/latex]<\/td>\n<td>29<\/td>\n<\/tr>\n<tr>\n<td>[latex]2,-15[\/latex]<\/td>\n<td>[latex]-13[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-2,15[\/latex]<\/td>\n<td>13<\/td>\n<\/tr>\n<tr>\n<td>[latex]3,-10[\/latex]<\/td>\n<td>[latex]-7[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-3,10[\/latex]<\/td>\n<td>7<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-id1167339303369\">So[latex]\\,p=-3\\,[\/latex]and[latex]\\,q=10.[\/latex]<\/p>\n\n<div id=\"fs-id1167339159132\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{cc}5{x}^{2}-3x+10x-6 \\hfill &amp; \\phantom{\\rule{2em}{0ex}}\\text{Rewrite the original expression as }a{x}^{2}+px+qx+c.\\hfill \\\\ x\\left(5x-3\\right)+2\\left(5x-3\\right)\\hfill &amp; \\phantom{\\rule{2em}{0ex}}\\text{Factor out the GCF of each part}.\\hfill \\\\ \\left(5x-3\\right)\\left(x+2\\right)\\hfill &amp; \\phantom{\\rule{2em}{0ex}}\\text{Factor out the GCF}\\text{\u200b}\\text{ of the expression}.\\hfill \\end{array}[\/latex][\/hidden-answer]<\/div>\n<\/div>\n<div id=\"fs-id1167339324695\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339324700\">We can check our work by multiplying. Use FOIL to confirm that[latex]\\,\\left(5x-3\\right)\\left(x+2\\right)=5{x}^{2}+7x-6.[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138014\" class=\"textbox tryit\">\n<div id=\"ti_01_05_03\">\n<div id=\"fs-id1167339143599\">\n<p id=\"fs-id1167339143600\">Factor a.[latex]\\,2{x}^{2}+9x+9\\,[\/latex]b.[latex]\\,6{x}^{2}+x-1[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339219115\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339219115\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339219115\"]\n<p id=\"fs-id1167339281315\">a.[latex]\\,\\left(2x+3\\right)\\left(x+3\\right)\\,[\/latex]b.[latex]\\,\\left(3x-1\\right)\\left(2x+1\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339300231\" class=\"bc-section section\">\n<h3>Factoring a Perfect Square Trinomial<\/h3>\n<p id=\"fs-id1167339300236\">A perfect square trinomial is a trinomial that can be written as the square of a binomial. Recall that when a binomial is squared, the result is the square of the first term added to twice the product of the two terms and the square of the last term.<\/p>\n\n<div id=\"fs-id1167339433578\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{ccc}\\hfill {a}^{2}+2ab+{b}^{2}&amp; =&amp; {\\left(a+b\\right)}^{2}\\hfill \\\\ &amp; \\text{and}&amp; \\\\ \\hfill {a}^{2}-2ab+{b}^{2}&amp; =&amp; {\\left(a-b\\right)}^{2}\\hfill \\end{array}[\/latex]<\/div>\n<p id=\"fs-id1167339303412\">We can use this equation to factor any perfect square trinomial.<\/p>\n\n<div id=\"fs-id1167339158176\" class=\"textbox key-takeaways\">\n<h3>Perfect Square Trinomials<\/h3>\n<p id=\"fs-id1167339321523\">A perfect square trinomial can be written as the square of a binomial:<\/p>\n\n<div id=\"Equation_01_05_01\">[latex]{a}^{2}+2ab+{b}^{2}={\\left(a+b\\right)}^{2}[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1167339168210\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339225968\"><strong>Given a perfect square trinomial, factor it into the square of a binomial.\n<\/strong><\/p>\n\n<ol id=\"fs-id1167339321581\" type=\"1\">\n \t<li>Confirm that the first and last term are perfect squares.<\/li>\n \t<li>Confirm that the middle term is twice the product of[latex]\\,ab.[\/latex]<\/li>\n \t<li>Write the factored form as[latex]\\,{\\left(a+b\\right)}^{2}.[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_04\" class=\"textbox examples\">\n<div id=\"fs-id1167339140179\">\n<div id=\"fs-id1167339140181\">\n<h3>Factoring a Perfect Square Trinomial<\/h3>\n<p id=\"fs-id1167339140186\">Factor[latex]\\,25{x}^{2}+20x+4.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339290269\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339290269\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339290269\"]\n<p id=\"fs-id1167339290271\">Notice that[latex]\\,25{x}^{2}\\,[\/latex]and[latex]\\,4\\,[\/latex]are perfect squares because[latex]\\,25{x}^{2}={\\left(5x\\right)}^{2}\\,[\/latex]and[latex]\\,4={2}^{2}.\\,[\/latex]Then check to see if the middle term is twice the product of[latex]\\,5x\\,[\/latex]and[latex]\\,2.\\,[\/latex]The middle term is, indeed, twice the product:[latex]\\,2\\left(5x\\right)\\left(2\\right)=20x.\\,[\/latex]Therefore, the trinomial is a perfect square trinomial and can be written as[latex]\\,{\\left(5x+2\\right)}^{2}.[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339212449\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_04\">\n<div id=\"fs-id1167339145226\">\n<p id=\"fs-id1167339145228\">Factor[latex]\\,49{x}^{2}-14x+1.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339220792\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339220792\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339220792\"]\n<p id=\"fs-id1167339220793\">[latex]{\\left(7x-1\\right)}^{2}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344862\" class=\"bc-section section\">\n<h3>Factoring a Difference of Squares<\/h3>\n<p id=\"fs-id1167339344867\">A difference of squares is a perfect square subtracted from a perfect square. Recall that a difference of squares can be rewritten as factors containing the same terms but opposite signs because the middle terms cancel each other out when the two factors are multiplied.<\/p>\n\n<div id=\"fs-id1167339184434\" class=\"unnumbered aligncenter\">[latex]{a}^{2}-{b}^{2}=\\left(a+b\\right)\\left(a-b\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339139364\">We can use this equation to factor any differences of squares.<\/p>\n\n<div id=\"fs-id1167339139367\" class=\"textbox key-takeaways\">\n<h3>Differences of Squares<\/h3>\n<p id=\"fs-id1167339212514\">A difference of squares can be rewritten as two factors containing the same terms but opposite signs.<\/p>\n\n<div id=\"Equation_01_05_02\">[latex]{a}^{2}-{b}^{2}=\\left(a+b\\right)\\left(a-b\\right)[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1167339243070\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339243077\"><strong>Given a difference of squares, factor it into binomials.<\/strong><\/p>\n\n<ol id=\"fs-id1167339259636\" type=\"1\">\n \t<li>Confirm that the first and last term are perfect squares.<\/li>\n \t<li>Write the factored form as[latex]\\,\\left(a+b\\right)\\left(a-b\\right).[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_05\" class=\"textbox examples\">\n<div id=\"fs-id1167339296405\">\n<div id=\"fs-id1167339296407\">\n<h3>Factoring a Difference of Squares<\/h3>\n<p id=\"fs-id1167339296412\">Factor[latex]\\,9{x}^{2}-25.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339296378\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339296378\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339296378\"]\n<p id=\"fs-id1167339432877\">Notice that[latex]\\,9{x}^{2}\\,[\/latex]and[latex]\\,25\\,[\/latex]are perfect squares because[latex]\\,9{x}^{2}={\\left(3x\\right)}^{2}\\,[\/latex]and[latex]\\,25={5}^{2}.\\,[\/latex]The polynomial represents a difference of squares and can be rewritten as[latex]\\,\\left(3x+5\\right)\\left(3x-5\\right).[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339432780\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_05\">\n<div id=\"fs-id1167339324582\">\n<p id=\"fs-id1167339324583\">Factor[latex]\\,81{y}^{2}-100.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339262683\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339262683\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339262683\"]\n<p id=\"fs-id1167339262684\">[latex]\\left(9y+10\\right)\\left(9y-10\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339240123\" class=\"precalculus qa textbox shaded\">\n<p id=\"fs-id1167339240130\"><strong>Is there a formula to factor the sum of squares?<\/strong><\/p>\n<p id=\"fs-id1167339240135\"><em>No. A sum of squares cannot be factored.<\/em><\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339281638\" class=\"bc-section section\">\n<h3>Factoring the Sum and Difference of Cubes<\/h3>\n<p id=\"fs-id1167339281643\">Now, we will look at two new special products: the sum and difference of cubes. Although the sum of squares cannot be factored, the sum of cubes can be factored into a binomial and a trinomial.<\/p>\n\n<div id=\"fs-id1167339281648\" class=\"unnumbered aligncenter\">[latex]{a}^{3}+{b}^{3}=\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339281668\">Similarly, the sum of cubes can be factored into a binomial and a trinomial, but with different signs.<\/p>\n\n<div id=\"fs-id1167339281486\" class=\"unnumbered aligncenter\">[latex]{a}^{3}-{b}^{3}=\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339281447\">We can use the acronym SOAP to remember the signs when factoring the sum or difference of cubes. The first letter of each word relates to the signs: <strong>S<\/strong>ame <strong>O<\/strong>pposite <strong>A<\/strong>lways <strong>P<\/strong>ositive. For example, consider the following example.<\/p>\n\n<div id=\"fs-id1167339281464\" class=\"unnumbered aligncenter\">[latex]{x}^{3}-{2}^{3}=\\left(x-2\\right)\\left({x}^{2}+2x+4\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339280881\">The sign of the first 2 is the <em>same<\/em> as the sign between[latex]\\,{x}^{3}-{2}^{3}.\\,[\/latex]The sign of the[latex]\\,2x\\,[\/latex]term is <em>opposite<\/em> the sign between[latex]\\,{x}^{3}-{2}^{3}.\\,[\/latex]And the sign of the last term, 4, is <em>always positive<\/em>.<\/p>\n\n<div id=\"fs-id1167339281550\" class=\"textbox key-takeaways\">\n<h3>Sum and Difference of Cubes<\/h3>\n<p id=\"fs-id1167339281559\">We can factor the sum of two cubes as<\/p>\n\n<div id=\"Equation_01_05_03\">[latex]{a}^{3}+{b}^{3}=\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339281287\">We can factor the difference of two cubes as<\/p>\n\n<div id=\"Equation_01_05_04\">[latex]{a}^{3}-{b}^{3}=\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right)[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1167339324784\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339324792\"><strong>Given a sum of cubes or difference of cubes, factor it.<\/strong><\/p>\n\n<ol id=\"fs-id1167339324796\" type=\"1\">\n \t<li>Confirm that the first and last term are cubes,[latex]\\,{a}^{3}+{b}^{3}\\,[\/latex]or[latex]\\,{a}^{3}-{b}^{3}.[\/latex]<\/li>\n \t<li>For a sum of cubes, write the factored form as[latex]\\,\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right).\\,[\/latex]For a difference of cubes, write the factored form as[latex]\\,\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right).[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_06\" class=\"textbox examples\">\n<div id=\"fs-id1167339240349\">\n<div id=\"fs-id1167339240351\">\n<h3>Factoring a Sum of Cubes<\/h3>\n<p id=\"fs-id1167339240357\">Factor[latex]\\,{x}^{3}+512.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339324945\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339324945\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339324945\"]Notice that[latex]\\,{x}^{3}\\,[\/latex]and[latex]\\,512\\,[\/latex]are cubes because[latex]\\,{8}^{3}=512.\\,[\/latex]Rewrite the sum of cubes as[latex]\\,\\left(x+8\\right)\\left({x}^{2}-8x+64\\right).[\/latex][\/hidden-answer]\n\n<\/div>\n<div id=\"fs-id1167339230837\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339230842\">After writing the sum of cubes this way, we might think we should check to see if the trinomial portion can be factored further. However, the trinomial portion cannot be factored, so we do not need to check.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339243153\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_06\">\n<div id=\"fs-id1167339243165\">\n<p id=\"fs-id1167339243166\">Factor the sum of cubes:[latex]\\,216{a}^{3}+{b}^{3}.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339296456\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339296456\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339296456\"]\n<p id=\"fs-id1167339296457\">[latex]\\left(6a+b\\right)\\left(36{a}^{2}-6ab+{b}^{2}\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"Example_01_05_07\" class=\"textbox examples\">\n<div id=\"fs-id1167339281618\">\n<div id=\"fs-id1167339281620\">\n<h3>Factoring a Difference of Cubes<\/h3>\n<p id=\"fs-id1167339281626\">Factor[latex]\\,8{x}^{3}-125.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339262635\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339262635\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339262635\"]Notice that[latex]\\,8{x}^{3}\\,[\/latex]and[latex]\\,125\\,[\/latex]are cubes because[latex]\\,8{x}^{3}={\\left(2x\\right)}^{3}\\,[\/latex]and[latex]\\,125={5}^{3}.\\,[\/latex]Write the difference of cubes as[latex]\\,\\left(2x-5\\right)\\left(4{x}^{2}+10x+25\\right).[\/latex][\/hidden-answer]\n\n<\/div>\n<div id=\"fs-id1167339223214\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339223219\">Just as with the sum of cubes, we will not be able to further factor the trinomial portion.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339259671\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_07\">\n<div id=\"fs-id1167339259683\">\n<p id=\"fs-id1167339259684\">Factor the difference of cubes:[latex]\\,1,000{x}^{3}-1.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339259713\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339259713\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339259713\"]\n<p id=\"fs-id1167339259714\">[latex]\\left(10x-1\\right)\\left(100{x}^{2}+10x+1\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339432601\" class=\"bc-section section\">\n<h3>Factoring Expressions with Fractional or Negative Exponents<\/h3>\n<p id=\"fs-id1167339432607\">Expressions with fractional or negative exponents can be factored by pulling out a GCF. Look for the variable or exponent that is common to each term of the expression and pull out that variable or exponent raised to the lowest power. These expressions follow the same factoring rules as those with integer exponents. For instance,[latex]\\,2{x}^{\\frac{1}{4}}+5{x}^{\\frac{3}{4}}\\,[\/latex]can be factored by pulling out[latex]\\,{x}^{\\frac{1}{4}}\\,[\/latex]and being rewritten as[latex]\\,{x}^{\\frac{1}{4}}\\left(2+5{x}^{\\frac{1}{2}}\\right).[\/latex]<\/p>\n\n<div id=\"Example_01_05_08\" class=\"textbox examples\">\n<div id=\"fs-id1167339196684\">\n<div id=\"fs-id1167339196686\">\n<h3>Factoring an Expression with Fractional or Negative Exponents<\/h3>\n<p id=\"fs-id1167339196691\">Factor[latex]\\,3x{\\left(x+2\\right)}^{\\frac{-1}{3}}+4{\\left(x+2\\right)}^{\\frac{2}{3}}.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339230930\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339230930\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339230930\"]\n<p id=\"fs-id1167339230932\">Factor out the term with the lowest value of the exponent. In this case, that would be[latex]\\,{\\left(x+2\\right)}^{-\\frac{1}{3}}.[\/latex]<\/p>\n\n<div id=\"fs-id1167339230987\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{cc}{\\left(x+2\\right)}^{-\\frac{1}{3}}\\left(3x+4\\left(x+2\\right)\\right)\\hfill &amp; \\phantom{\\rule{2em}{0ex}}\\text{Factor out the GCF}.\\hfill \\\\ {\\left(x+2\\right)}^{-\\frac{1}{3}}\\left(3x+4x+8\\right)\\hfill &amp; \\phantom{\\rule{2em}{0ex}}\\text{Simplify}.\\hfill \\\\ {\\left(x+2\\right)}^{-\\frac{1}{3}}\\left(7x+8\\right)\\hfill &amp; \\end{array}[\/latex][\/hidden-answer]<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339309570\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_08\">\n<div id=\"fs-id1167339309581\">\n<p id=\"fs-id1167339309582\">Factor[latex]\\,2{\\left(5a-1\\right)}^{\\frac{3}{4}}+7a{\\left(5a-1\\right)}^{-\\frac{1}{4}}.[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339273714\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339273714\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339273714\"]\n<p id=\"fs-id1167339273715\">[latex]{\\left(5a-1\\right)}^{-\\frac{1}{4}}\\left(17a-2\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339306561\" class=\"precalculus media\">\n<p id=\"fs-id1167339306568\">Access these online resources for additional instruction and practice with factoring polynomials.<\/p>\n\n<ul id=\"fs-id1167339306573\">\n \t<li><a href=\"http:\/\/openstaxcollege.org\/l\/findgcftofact\">Identify GCF<\/a><\/li>\n \t<li><a href=\"http:\/\/openstaxcollege.org\/l\/facttrinom1\">Factor Trinomials when a Equals 1<\/a><\/li>\n \t<li><a href=\"http:\/\/openstaxcollege.org\/l\/facttrinom2\">Factor Trinomials when a is not equal to 1<\/a><\/li>\n \t<li><a href=\"http:\/\/openstaxcollege.org\/l\/sumdifcube\">Factor Sum or Difference of Cubes<\/a><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339306605\" class=\"key-equations\">\n<h3>Key Equations<\/h3>\n<table id=\"fs-id1167339306612\" summary=\"..\">\n<tbody>\n<tr>\n<td>difference of squares<\/td>\n<td>[latex]{a}^{2}-{b}^{2}=\\left(a+b\\right)\\left(a-b\\right)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>perfect square trinomial<\/td>\n<td>[latex]{a}^{2}+2ab+{b}^{2}={\\left(a+b\\right)}^{2}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>sum of cubes<\/td>\n<td>[latex]{a}^{3}+{b}^{3}=\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>difference of cubes<\/td>\n<td>[latex]{a}^{3}-{b}^{3}=\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right)[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"fs-id1167339199496\" class=\"textbox key-takeaways\">\n<ul id=\"fs-id1167339199500\">\n \t<li>The greatest common factor, or GCF, can be factored out of a polynomial. Checking for a GCF should be the first step in any factoring problem. See <a class=\"autogenerated-content\" href=\"#Example_01_05_01\">(Figure)<\/a>.<\/li>\n \t<li>Trinomials with leading coefficient 1 can be factored by finding numbers that have a product of the third term and a sum of the second term. See <a class=\"autogenerated-content\" href=\"#Example_01_05_02\">(Figure)<\/a>.<\/li>\n \t<li>Trinomials can be factored using a process called factoring by grouping. See <a class=\"autogenerated-content\" href=\"#Example_01_05_03\">(Figure)<\/a>.<\/li>\n \t<li>Perfect square trinomials and the difference of squares are special products and can be factored using equations. See <a class=\"autogenerated-content\" href=\"#Example_01_05_04\">(Figure)<\/a> and <a class=\"autogenerated-content\" href=\"#Example_01_05_05\">(Figure)<\/a>.<\/li>\n \t<li>The sum of cubes and the difference of cubes can be factored using equations. See <a class=\"autogenerated-content\" href=\"#Example_01_05_06\">(Figure)<\/a> and <a class=\"autogenerated-content\" href=\"#Example_01_05_07\">(Figure)<\/a>.<\/li>\n \t<li>Polynomials containing fractional and negative exponents can be factored by pulling out a GCF. See <a class=\"autogenerated-content\" href=\"#Example_01_05_08\">(Figure)<\/a>.<\/li>\n<\/ul>\n<\/div>\n<div id=\"fs-id1167339220212\" class=\"textbox exercises\">\n<div id=\"fs-id1167339220216\" class=\"bc-section section\">\n<h4>Verbal<\/h4>\n<div id=\"fs-id1167339220221\">\n<div id=\"fs-id1167339220222\">\n<p id=\"fs-id1167339220223\">If the terms of a polynomial do not have a GCF, does that mean it is not factorable? Explain.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339220227\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339220227\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339220227\"]\n<p id=\"fs-id1167339220228\">The terms of a polynomial do not have to have a common factor for the entire polynomial to be factorable. For example,[latex]\\,4{x}^{2}\\,[\/latex]and[latex]\\,-9{y}^{2}\\,[\/latex]don\u2019t have a common factor, but the whole polynomial is still factorable:[latex]\\,4{x}^{2}-9{y}^{2}=\\left(2x+3y\\right)\\left(2x-3y\\right).[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226305\">\n<div id=\"fs-id1167339226306\">\n<p id=\"fs-id1167339226307\">A polynomial is factorable, but it is not a perfect square trinomial or a difference of two squares. Can you factor the polynomial without finding the GCF?<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226312\">\n<div id=\"fs-id1167339226313\">\n<p id=\"fs-id1167339226314\">How do you factor by grouping?<\/p>\n\n<\/div>\n<div id=\"fs-id1167339226317\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339226317\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339226317\"]\n<p id=\"fs-id1167339226318\">Divide the[latex]\\,x\\,[\/latex]term into the sum of two terms, factor each portion of the expression separately, and then factor out the GCF of the entire expression.<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226337\" class=\"bc-section section\">\n<h4>Algebraic<\/h4>\n<p id=\"fs-id1167339226343\">For the following exercises, find the greatest common factor.<\/p>\n\n<div id=\"fs-id1167339226346\">\n<div id=\"fs-id1167339226347\">\n<p id=\"fs-id1167339226348\">[latex]14x+4xy-18x{y}^{2}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226385\">\n<div id=\"fs-id1167339226386\">\n<p id=\"fs-id1167339226388\">[latex]49m{b}^{2}-35{m}^{2}ba+77m{a}^{2}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339218641\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339218641\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339218641\"]\n<p id=\"fs-id1167339218642\">[latex]7m[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339218656\">\n<div id=\"fs-id1167339218657\">\n<p id=\"fs-id1167339218658\">[latex]30{x}^{3}y-45{x}^{2}{y}^{2}+135x{y}^{3}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339218720\">\n<div id=\"fs-id1167339218721\">\n<p id=\"fs-id1167339218722\">[latex]200{p}^{3}{m}^{3}-30{p}^{2}{m}^{3}+40{m}^{3}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339426591\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339426591\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339426591\"]\n<p id=\"fs-id1167339426592\">[latex]10{m}^{3}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339426613\">\n<div id=\"fs-id1167339426614\">\n<p id=\"fs-id1167339426615\">[latex]36{j}^{4}{k}^{2}-18{j}^{3}{k}^{3}+54{j}^{2}{k}^{4}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339426694\">\n<div id=\"fs-id1167339426695\">\n<p id=\"fs-id1167339426696\">[latex]6{y}^{4}-2{y}^{3}+3{y}^{2}-y[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339196474\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339196474\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339196474\"]\n<p id=\"fs-id1167339196475\">[latex]y[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<p id=\"fs-id1167339196483\">For the following exercises, factor by grouping.<\/p>\n\n<div id=\"fs-id1167339196486\">\n<div id=\"fs-id1167339196488\">\n<p id=\"fs-id1167339196489\">[latex]6{x}^{2}+5x-4[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339196521\">\n<div id=\"fs-id1167339196522\">\n<p id=\"fs-id1167339196523\">[latex]2{a}^{2}+9a-18[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339196555\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339196555\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339196555\"]\n<p id=\"fs-id1167339196556\">[latex]\\left(2a-3\\right)\\left(a+6\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339260424\">\n<div id=\"fs-id1167339260425\">\n<p id=\"fs-id1167339260426\">[latex]6{c}^{2}+41c+63[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339260458\">\n<div id=\"fs-id1167339260459\">\n<p id=\"fs-id1167339260460\">[latex]6{n}^{2}-19n-11[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339260492\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339260492\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339260492\"]\n<p id=\"fs-id1167339260493\">[latex]\\left(3n-11\\right)\\left(2n+1\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339260541\">\n<div id=\"fs-id1167339260542\">\n<p id=\"fs-id1167339260543\">[latex]20{w}^{2}-47w+24[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339303598\">\n<div id=\"fs-id1167339303599\">\n<p id=\"fs-id1167339303600\">[latex]2{p}^{2}-5p-7[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339303632\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339303632\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339303632\"]\n<p id=\"fs-id1167339303633\">[latex]\\left(p+1\\right)\\left(2p-7\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<p id=\"fs-id1167339303679\">For the following exercises, factor the polynomial.<\/p>\n\n<div id=\"fs-id1167339303682\">\n<div id=\"fs-id1167339303683\">\n<p id=\"fs-id1167339303684\">[latex]7{x}^{2}+48x-7[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339303716\">\n<div id=\"fs-id1167339303717\">\n<p id=\"fs-id1167339303718\">[latex]10{h}^{2}-9h-9[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339239045\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339239045\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339239045\"]\n<p id=\"fs-id1167339239046\">[latex]\\left(5h+3\\right)\\left(2h-3\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239094\">\n<div id=\"fs-id1167339239095\">\n<p id=\"fs-id1167339239096\">[latex]2{b}^{2}-25b-247[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239128\">\n<div id=\"fs-id1167339239129\">\n<p id=\"fs-id1167339239130\">[latex]9{d}^{2}-73d+8[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339239162\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339239162\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339239162\"]\n<p id=\"fs-id1167339239163\">[latex]\\left(9d-1\\right)\\left(d-8\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339321370\">\n<div id=\"fs-id1167339321372\">\n<p id=\"fs-id1167339321373\">[latex]90{v}^{2}-181v+90[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339321405\">\n<div id=\"fs-id1167339321406\">\n<p id=\"fs-id1167339321407\">[latex]12{t}^{2}+t-13[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339321437\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339321437\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339321437\"]\n<p id=\"fs-id1167339321438\">[latex]\\left(12t+13\\right)\\left(t-1\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339321484\">\n<div id=\"fs-id1167339321485\">\n<p id=\"fs-id1167339321486\">[latex]2{n}^{2}-n-15[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344423\">\n<div id=\"fs-id1167339344424\">\n<p id=\"fs-id1167339344426\">[latex]16{x}^{2}-100[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339344451\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339344451\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339344451\"]\n[latex]\\left(4x+10\\right)\\left(4x-10\\right)[\/latex][\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344500\">\n<div id=\"fs-id1167339344501\">\n<p id=\"fs-id1167339344502\">[latex]25{y}^{2}-196[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344528\">\n<div id=\"fs-id1167339344529\">\n<p id=\"fs-id1167339344530\">[latex]121{p}^{2}-169[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339344556\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339344556\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339344556\"]\n<p id=\"fs-id1167339344557\">[latex]\\left(11p+13\\right)\\left(11p-13\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138818\">\n<div id=\"fs-id1167339138819\">\n<p id=\"fs-id1167339138820\">[latex]4{m}^{2}-9[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138845\">\n<div id=\"fs-id1167339138846\">\n<p id=\"fs-id1167339138848\">[latex]361{d}^{2}-81[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339138873\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339138873\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339138873\"]\n<p id=\"fs-id1167339138874\">[latex]\\left(19d+9\\right)\\left(19d-9\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138922\">\n<div id=\"fs-id1167339138923\">\n<p id=\"fs-id1167339138924\">[latex]324{x}^{2}-121[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339273782\">\n<div id=\"fs-id1167339273783\">\n<p id=\"fs-id1167339273784\">[latex]144{b}^{2}-25{c}^{2}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339273818\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339273818\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339273818\"]\n<p id=\"fs-id1167339273819\">[latex]\\left(12b+5c\\right)\\left(12b-5c\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339273871\">\n<div id=\"fs-id1167339273872\">\n<p id=\"fs-id1167339273873\">[latex]16{a}^{2}-8a+1[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339273905\">\n<div id=\"fs-id1167339273906\">\n<p id=\"fs-id1167339273907\">[latex]49{n}^{2}+168n+144[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339227654\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339227654\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339227654\"]\n<p id=\"fs-id1167339227655\">[latex]{\\left(7n+12\\right)}^{2}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339227694\">\n<div id=\"fs-id1167339227695\">\n<p id=\"fs-id1167339227696\">[latex]121{x}^{2}-88x+16[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339227728\">\n<div id=\"fs-id1167339227729\">\n<p id=\"fs-id1167339227730\">[latex]225{y}^{2}+120y+16[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339227762\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339227762\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339227762\"]\n<p id=\"fs-id1167339227763\">[latex]{\\left(15y+4\\right)}^{2}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339227802\">\n<div id=\"fs-id1167339227803\">\n<p id=\"fs-id1167339227804\">[latex]{m}^{2}-20m+100[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339213934\">\n<div id=\"fs-id1167339213935\">\n<p id=\"fs-id1167339213936\">[latex]25{p}^{2}-120m+144[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339213968\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339213968\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339213968\"]\n<p id=\"fs-id1167339213969\">[latex]{\\left(5p-12\\right)}^{2}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339214008\">\n<div id=\"fs-id1167339214009\">\n<p id=\"fs-id1167339214010\">[latex]36{q}^{2}+60q+25[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<p id=\"fs-id1167339214042\">For the following exercises, factor the polynomials.<\/p>\n\n<div>\n<div>\n<p id=\"fs-id1167339214047\">[latex]{x}^{3}+216[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339214070\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339214070\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339214070\"]\n<p id=\"fs-id1167339214072\">[latex]\\left(x+6\\right)\\left({x}^{2}-6x+36\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339222855\">\n<div id=\"fs-id1167339222856\">\n<p id=\"fs-id1167339222857\">[latex]27{y}^{3}-8[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339222883\">\n<div id=\"fs-id1167339222884\">\n<p id=\"fs-id1167339222885\">[latex]125{a}^{3}+343[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339222911\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339222911\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339222911\"]\n<p id=\"fs-id1167339222912\">[latex]\\left(5a+7\\right)\\left(25{a}^{2}-35a+49\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339222974\">\n<div id=\"fs-id1167339222975\">\n<p id=\"fs-id1167339222976\">[latex]{b}^{3}-8{d}^{3}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339223008\">\n<div id=\"fs-id1167339223009\">\n<p id=\"fs-id1167339223010\">[latex]64{x}^{3}-125[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339223036\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339223036\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339223036\"]\n<p id=\"fs-id1167339223037\">[latex]\\left(4x-5\\right)\\left(16{x}^{2}+20x+25\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339280936\">\n<div id=\"fs-id1167339280937\">\n<p id=\"fs-id1167339280938\">[latex]729{q}^{3}+1331[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339280964\">\n<div id=\"fs-id1167339280965\">\n<p id=\"fs-id1167339280966\">[latex]125{r}^{3}+1,728{s}^{3}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339281004\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339281004\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339281004\"]\n<p id=\"fs-id1167339281006\">[latex]\\left(5r+12s\\right)\\left(25{r}^{2}-60rs+144{s}^{2}\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339281080\">\n<div id=\"fs-id1167339281081\">\n<p id=\"fs-id1167339281082\">[latex]4x{\\left(x-1\\right)}^{-\\frac{2}{3}}+3{\\left(x-1\\right)}^{\\frac{1}{3}}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339225624\">\n<div id=\"fs-id1167339225626\">\n<p id=\"fs-id1167339225627\">[latex]3c{\\left(2c+3\\right)}^{-\\frac{1}{4}}-5{\\left(2c+3\\right)}^{\\frac{3}{4}}[\/latex]<\/p>\n\n<\/div>\n<div>\n<div class=\"textbox shaded\">[reveal-answer q=\"fs-id1167339225726\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339225726\"]\n<p id=\"fs-id1167339225726\">[latex]{\\left(2c+3\\right)}^{-\\frac{1}{4}}\\left(-7c-15\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339225798\">\n<div id=\"fs-id1167339317629\">\n<p id=\"fs-id1167339317630\">[latex]3t{\\left(10t+3\\right)}^{\\frac{1}{3}}+7{\\left(10t+3\\right)}^{\\frac{4}{3}}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339317726\">\n<div id=\"fs-id1167339317727\">\n<p id=\"fs-id1167339317728\">[latex]14x{\\left(x+2\\right)}^{-\\frac{2}{5}}+5{\\left(x+2\\right)}^{\\frac{3}{5}}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339317822\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339317822\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339317822\"]\n<p id=\"fs-id1167339317823\">[latex]{\\left(x+2\\right)}^{-\\frac{2}{5}}\\left(19x+10\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339437841\">\n<div id=\"fs-id1167339437842\">\n<p id=\"fs-id1167339437843\">[latex]9y{\\left(3y-13\\right)}^{\\frac{1}{5}}-2{\\left(3y-13\\right)}^{\\frac{6}{5}}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339437939\">\n<div>\n<p id=\"fs-id1167339437941\">[latex]5z{\\left(2z-9\\right)}^{-\\frac{3}{2}}+11{\\left(2z-9\\right)}^{-\\frac{1}{2}}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339438041\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339438041\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339438041\"]\n<p id=\"fs-id1167339438042\">[latex]{\\left(2z-9\\right)}^{-\\frac{3}{2}}\\left(27z-99\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339315699\">\n<div id=\"fs-id1167339315700\">\n<p id=\"fs-id1167339315701\">[latex]6d{\\left(2d+3\\right)}^{-\\frac{1}{6}}+5{\\left(2d+3\\right)}^{\\frac{5}{6}}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339315800\" class=\"bc-section section\">\n<h4>Real-World Applications<\/h4>\n<p id=\"fs-id1167339315805\">For the following exercises, consider this scenario:<\/p>\n<p id=\"fs-id1167339315809\">Charlotte has appointed a chairperson to lead a city beautification project. The first act is to install statues and fountains in one of the city\u2019s parks. The park is a rectangle with an area of[latex]\\,98{x}^{2}+105x-27\\,[\/latex]m<sup>2<\/sup>, as shown in the figure below. The length and width of the park are perfect factors of the area.<\/p>\n<span id=\"fs-id1167339315854\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3252\/2018\/07\/19132158\/CNX_CAT_Figure_01_05_201.jpg\" alt=\"A rectangle that\u2019s textured to look like a field. The field is labeled: l times w = ninety-eight times x squared plus one hundred five times x minus twenty-seven.\"><\/span>\n<div id=\"fs-id1167339315866\">\n<div id=\"fs-id1167339315867\">\n<p id=\"fs-id1167339315868\">Factor by grouping to find the length and width of the park.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339315871\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339315871\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339315871\"]\n<p id=\"fs-id1167339315872\">[latex]\\left(14x-3\\right)\\left(7x+9\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239178\">\n<div id=\"fs-id1167339239179\">\n<p id=\"fs-id1167339239180\">A statue is to be placed in the center of the park. The area of the base of the statue is[latex]\\,4{x}^{2}+12x+9{\\text{m}}^{2}.\\,[\/latex]Factor the area to find the lengths of the sides of the statue.<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239218\">\n<div id=\"fs-id1167339239219\">\n<p id=\"fs-id1167339239220\">At the northwest corner of the park, the city is going to install a fountain. The area of the base of the fountain is[latex]\\,9{x}^{2}-25{\\text{m}}^{2}.\\,[\/latex]Factor the area to find the lengths of the sides of the fountain.<\/p>\n\n<\/div>\n<div id=\"fs-id1167339239252\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339239252\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339239252\"]\n<p id=\"fs-id1167339239254\">[latex]\\left(3x+5\\right)\\left(3x-5\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<p id=\"fs-id1167339239302\">For the following exercise, consider the following scenario:<\/p>\n<p id=\"fs-id1167339239305\">A school is installing a flagpole in the central plaza. The plaza is a square with side length 100 yd. as shown in the figure below. The flagpole will take up a square plot with area[latex]\\,{x}^{2}-6x+9[\/latex]yd<sup>2<\/sup>.<\/p>\n<span id=\"fs-id1167339239346\"><img src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3252\/2018\/07\/19132200\/CNX_CAT_Figure_01_05_202.jpg\" alt=\"A square that\u2019s textured to look like a field with a missing piece in the shape of a square in the center. The sides of the larger square are labeled: 100 yards. The center square is labeled: Area: x squared minus six times x plus nine.\"><\/span>\n<div id=\"fs-id1167339239356\">\n<div id=\"fs-id1167339239358\">\n<p id=\"fs-id1167339239359\">Find the length of the base of the flagpole by factoring.<\/p>\n\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239363\" class=\"bc-section section\">\n<h4>Extensions<\/h4>\n<p id=\"fs-id1167339239368\">For the following exercises, factor the polynomials completely.<\/p>\n\n<div id=\"fs-id1167339239371\">\n<div id=\"fs-id1167339239372\">\n<p id=\"fs-id1167339239374\">[latex]16{x}^{4}-200{x}^{2}+625[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339239413\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339239413\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339239413\"]\n<p id=\"fs-id1167339239414\">[latex]{\\left(2x+5\\right)}^{2}{\\left(2x-5\\right)}^{2}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339240884\">\n<div id=\"fs-id1167339240886\">\n<p id=\"fs-id1167339240887\">[latex]81{y}^{4}-256[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339240912\">\n<div id=\"fs-id1167339240913\">\n<p id=\"fs-id1167339240914\">[latex]16{z}^{4}-2,401{a}^{4}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339240953\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339240953\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339240953\"]\n<p id=\"fs-id1167339240954\">[latex]\\left(4{z}^{2}+49{a}^{2}\\right)\\left(2z+7a\\right)\\left(2z-7a\\right)[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339241043\">\n<div id=\"fs-id1167339241044\">\n<p id=\"fs-id1167339241045\">[latex]5x{\\left(3x+2\\right)}^{-\\frac{2}{4}}+{\\left(12x+8\\right)}^{\\frac{3}{2}}[\/latex]<\/p>\n\n<\/div>\n<\/div>\n<div id=\"fs-id1167339433017\">\n<div id=\"fs-id1167339433018\">\n<p id=\"fs-id1167339433019\">[latex]{\\left(32{x}^{3}+48{x}^{2}-162x-243\\right)}^{-1}[\/latex]<\/p>\n\n<\/div>\n<div id=\"fs-id1167339433090\" class=\"solution textbox shaded\">[reveal-answer q=\"fs-id1167339433090\"]Show Solution[\/reveal-answer]\n[hidden-answer a=\"fs-id1167339433090\"]\n<p id=\"fs-id1167339433091\">[latex]\\frac{1}{\\left(4x+9\\right)\\left(4x-9\\right)\\left(2x+3\\right)}[\/latex]<\/p>\n[\/hidden-answer]\n\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Glossary<\/h3>\n<dl id=\"fs-id1167339433176\">\n \t<dt>factor by grouping<\/dt>\n \t<dd id=\"fs-id1167339433179\">a method for factoring a trinomial in the form[latex]\\,a{x}^{2}+bx+c\\,[\/latex]by dividing the <em>x<\/em> term into the sum of two terms, factoring each portion of the expression separately, and then factoring out the GCF of the entire expression<\/dd>\n<\/dl>\n<dl id=\"fs-id1167339433223\">\n \t<dt>greatest common factor<\/dt>\n \t<dd id=\"fs-id1167339433226\">the largest polynomial that divides evenly into each polynomial<\/dd>\n<\/dl>\n<\/div>","rendered":"<div class=\"textbox learning-objectives\">\n<h3>Learning Objectives<\/h3>\n<p>In this section students will:<\/p>\n<ul>\n<li>Factor the greatest common factor of a polynomial.<\/li>\n<li>Factor a trinomial.<\/li>\n<li>Factor by grouping.<\/li>\n<li>Factor a perfect square trinomial.<\/li>\n<li>Factor a difference of squares.<\/li>\n<li>Factor the sum and difference of cubes.<\/li>\n<li>Factor expressions using fractional or negative exponents.<\/li>\n<\/ul>\n<\/div>\n<p id=\"fs-id1167339261641\">Imagine that we are trying to find the area of a lawn so that we can determine how much grass seed to purchase. The lawn is the green portion in <a class=\"autogenerated-content\" href=\"#Figure_01_05_001\">(Figure)<\/a>.<\/p>\n<div id=\"Figure_01_05_001\" class=\"small wp-caption aligncenter\">\n<figure style=\"width: 487px\" class=\"wp-caption aligncenter small\"><img loading=\"lazy\" decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3252\/2018\/07\/19132149\/CNX_CAT_Figure_01_05_001.jpg\" alt=\"A large rectangle with smaller squares and a rectangle inside. The length of the outer rectangle is 6x and the width is 10x. The side length of the squares is 4 and the height of the width of the inner rectangle is 4.\" width=\"487\" height=\"259\" \/><figcaption class=\"wp-caption-text\"><strong>Figure 1.<\/strong><\/figcaption><\/figure>\n<\/div>\n<p id=\"fs-id1167339156365\">The area of the entire region can be found using the formula for the area of a rectangle.<\/p>\n<div id=\"fs-id1167339219134\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{ccc}\\hfill A& =& lw\\hfill \\\\ & =& 10x\\cdot 6x\\hfill \\\\ & =& 60{x}^{2}{\\text{ units}}^{2}\\hfill \\end{array}[\/latex]<\/div>\n<p id=\"fs-id1167339216289\">The areas of the portions that do not require grass seed need to be subtracted from the area of the entire region. The two square regions each have an area of[latex]\\,A={s}^{2}={4}^{2}=16\\,[\/latex]units<sup>2<\/sup>. The other rectangular region has one side of length[latex]\\,10x-8\\,[\/latex]and one side of length[latex]\\,4,[\/latex]giving an area of[latex]\\,A=lw=4\\left(10x-8\\right)=40x-32\\,[\/latex]units<sup>2<\/sup>. So the region that must be subtracted has an area of[latex]\\,2\\left(16\\right)+40x-32=40x\\,[\/latex]units<sup>2<\/sup>.<\/p>\n<p id=\"fs-id1167339224267\">The area of the region that requires grass seed is found by subtracting[latex]\\,60{x}^{2}-40x\\,[\/latex]units<sup>2<\/sup>. This area can also be expressed in factored form as[latex]\\,20x\\left(3x-2\\right)\\,[\/latex]units<sup>2<\/sup>. We can confirm that this is an equivalent expression by multiplying.<\/p>\n<p id=\"fs-id1167339243193\">Many polynomial expressions can be written in simpler forms by factoring. In this section, we will look at a variety of methods that can be used to factor polynomial expressions.<\/p>\n<div id=\"fs-id1167339224262\" class=\"bc-section section\">\n<h3>Factoring the Greatest Common Factor of a Polynomial<\/h3>\n<p id=\"fs-id1167339226451\">When we study fractions, we learn that the greatest common factor (GCF) of two numbers is the largest number that divides evenly into both numbers. For instance,[latex]\\,4\\,[\/latex]is the GCF of[latex]\\,16\\,[\/latex]and[latex]\\,20\\,[\/latex]because it is the largest number that divides evenly into both[latex]\\,16\\,[\/latex]and[latex]\\,20\\,[\/latex]The GCF of polynomials works the same way:[latex]\\,4x\\,[\/latex]is the GCF of[latex]\\,16x\\,[\/latex]and[latex]\\,20{x}^{2}\\,[\/latex]because it is the largest polynomial that divides evenly into both[latex]\\,16x\\,[\/latex]and[latex]\\,20{x}^{2}.[\/latex]<\/p>\n<p id=\"fs-id1167339171909\">When factoring a polynomial expression, our first step should be to check for a GCF. Look for the GCF of the coefficients, and then look for the GCF of the variables.<\/p>\n<div id=\"fs-id1167339144723\" class=\"textbox key-takeaways\">\n<h3>Greatest Common Factor<\/h3>\n<p id=\"fs-id1167339150653\">The greatest common factor (GCF) of polynomials is the largest polynomial that divides evenly into the polynomials.<\/p>\n<\/div>\n<div id=\"fs-id1167339220518\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339145267\"><strong>Given a polynomial expression, factor out the greatest common factor.<br \/>\n<\/strong><\/p>\n<ol id=\"fs-id1167339147626\" type=\"1\">\n<li>Identify the GCF of the coefficients.<\/li>\n<li>Identify the GCF of the variables.<\/li>\n<li>Combine to find the GCF of the expression.<\/li>\n<li>Determine what the GCF needs to be multiplied by to obtain each term in the expression.<\/li>\n<li>Write the factored expression as the product of the GCF and the sum of the terms we need to multiply by.<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_01\" class=\"textbox examples\">\n<div id=\"fs-id1167339243738\">\n<div id=\"fs-id1167339156623\">\n<h3>Factoring the Greatest Common Factor<\/h3>\n<p id=\"fs-id1167339318400\">Factor[latex]\\,6{x}^{3}{y}^{3}+45{x}^{2}{y}^{2}+21xy.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339167326\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339212882\">First, find the GCF of the expression. The GCF of[latex]\\,6,45,[\/latex]and[latex]\\,21\\,[\/latex]is[latex]\\,3.\\,[\/latex]The GCF of[latex]\\,{x}^{3},{x}^{2},[\/latex]and[latex]\\,x\\,[\/latex]is[latex]\\,x.\\,[\/latex](Note that the GCF of a set of expressions in the form[latex]\\,{x}^{n}\\,[\/latex]will always be the exponent of lowest degree.) And the GCF of[latex]\\,{y}^{3},{y}^{2},[\/latex]and[latex]\\,y\\,[\/latex]is[latex]\\,y.\\,[\/latex]Combine these to find the GCF of the polynomial,[latex]\\,3xy.[\/latex]<\/p>\n<p id=\"fs-id1167339212530\">Next, determine what the GCF needs to be multiplied by to obtain each term of the polynomial. We find that[latex]\\,3xy\\left(2{x}^{2}{y}^{2}\\right)=6{x}^{3}{y}^{3},3xy\\left(15xy\\right)=45{x}^{2}{y}^{2},[\/latex]and[latex]\\,3xy\\left(7\\right)=21xy.[\/latex]<\/p>\n<p id=\"fs-id1167339330136\">Finally, write the factored expression as the product of the GCF and the sum of the terms we needed to multiply by.<\/p>\n<div id=\"fs-id1167339186024\" class=\"unnumbered aligncenter\">[latex]\\left(3xy\\right)\\left(2{x}^{2}{y}^{2}+15xy+7\\right)[\/latex]<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339276172\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339136986\">After factoring, we can check our work by multiplying. Use the distributive property to confirm that[latex]\\,\\left(3xy\\right)\\left(2{x}^{2}{y}^{2}+15xy+7\\right)=6{x}^{3}{y}^{3}+45{x}^{2}{y}^{2}+21xy.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339144942\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_01\">\n<div id=\"fs-id1167339344600\">\n<p id=\"fs-id1167339344602\">Factor[latex]\\,x\\left({b}^{2}-a\\right)+6\\left({b}^{2}-a\\right)\\,[\/latex]by pulling out the GCF.<\/p>\n<\/div>\n<div id=\"fs-id1167339152770\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339152771\">[latex]\\left({b}^{2}-a\\right)\\left(x+6\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339432992\" class=\"bc-section section\">\n<h3>Factoring a Trinomial with Leading Coefficient 1<\/h3>\n<p id=\"fs-id1167339432966\">Although we should always begin by looking for a GCF, pulling out the GCF is not the only way that polynomial expressions can be factored. The polynomial[latex]\\,{x}^{2}+5x+6\\,[\/latex]has a GCF of 1, but it can be written as the product of the factors[latex]\\,\\left(x+2\\right)\\,[\/latex]and[latex]\\,\\left(x+3\\right).[\/latex]<\/p>\n<p id=\"fs-id1167339318134\">Trinomials of the form[latex]\\,{x}^{2}+bx+c\\,[\/latex]can be factored by finding two numbers with a product of[latex]c\\,[\/latex]and a sum of[latex]\\,b.\\,[\/latex]The trinomial[latex]\\,{x}^{2}+10x+16,[\/latex]for example, can be factored using the numbers[latex]\\,2\\,[\/latex]and[latex]\\,8\\,[\/latex]because the product of those numbers is[latex]\\,16\\,[\/latex]and their sum is[latex]\\,10.\\,[\/latex]The trinomial can be rewritten as the product of[latex]\\,\\left(x+2\\right)\\,[\/latex]and[latex]\\,\\left(x+8\\right).[\/latex]<\/p>\n<div id=\"fs-id1167339149443\" class=\"textbox key-takeaways\">\n<h3>Factoring a Trinomial with Leading Coefficient 1<\/h3>\n<p id=\"fs-id1167339176943\">A trinomial of the form[latex]\\,{x}^{2}+bx+c\\,[\/latex]can be written in factored form as[latex]\\,\\left(x+p\\right)\\left(x+q\\right)\\,[\/latex]where[latex]\\,pq=c\\,[\/latex]and[latex]\\,p+q=b.[\/latex]<\/p>\n<\/div>\n<div class=\"precalculus qa textbox shaded\">\n<p id=\"fs-id1167339329107\"><strong>Can every trinomial be factored as a product of binomials?<\/strong><\/p>\n<p id=\"fs-id1167339433613\"><em>No. Some polynomials cannot be factored. These polynomials are said to be prime.<\/em><\/p>\n<\/div>\n<div id=\"fs-id1167339157766\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339231645\"><strong>Given a trinomial in the form[latex]\\,{x}^{2}+bx+c,[\/latex]factor it.<\/strong><\/p>\n<ol id=\"fs-id1167339151903\" type=\"1\">\n<li>List factors of[latex]\\,c.[\/latex]<\/li>\n<li>Find[latex]\\,p\\,[\/latex]and[latex]\\,q,[\/latex]a pair of factors of[latex]\\,c\\,[\/latex]with a sum of[latex]\\,b.[\/latex]<\/li>\n<li>Write the factored expression[latex]\\,\\left(x+p\\right)\\left(x+q\\right).[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_02\" class=\"textbox examples\">\n<div id=\"fs-id1167339139078\">\n<div id=\"fs-id1167339185064\">\n<h3>Factoring a Trinomial with Leading Coefficient 1<\/h3>\n<p id=\"fs-id1167339185070\">Factor[latex]\\,{x}^{2}+2x-15.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339281370\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339281372\">We have a trinomial with leading coefficient[latex]\\,1,b=2,[\/latex]and[latex]\\,c=-15.\\,[\/latex]We need to find two numbers with a product of[latex]\\,-15\\,[\/latex]and a sum of[latex]\\,2.\\,[\/latex]In <a class=\"autogenerated-content\" href=\"#Table_01_05_01\">(Figure)<\/a>, we list factors until we find a pair with the desired sum.<\/p>\n<table id=\"Table_01_05_01\" summary=\"A table with five rows and two columns. The first row has columns labeled: Factors of -15 and Sum of Factors. The entries in the first column are: 1, -15; -1, 15; 3, -5; and -3,5. The entries in the second column are: -14, 14, -2, and 2.\">\n<caption>&nbsp;<\/caption>\n<thead>\n<tr>\n<th>Factors of[latex]\\,-15[\/latex]<\/th>\n<th>Sum of Factors<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]1,-15[\/latex]<\/td>\n<td>[latex]-14[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-1,15[\/latex]<\/td>\n<td>14<\/td>\n<\/tr>\n<tr>\n<td>[latex]3,-5[\/latex]<\/td>\n<td>[latex]-2[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-3,5[\/latex]<\/td>\n<td>2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-id1167339137924\">Now that we have identified[latex]\\,p\\,[\/latex]and[latex]\\,q\\,[\/latex]as[latex]\\,-3\\,[\/latex]and[latex]\\,5,[\/latex]write the factored form as[latex]\\,\\left(x-3\\right)\\left(x+5\\right).[\/latex]<\/details>\n<\/p>\n<\/div>\n<div id=\"fs-id1167339168604\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339290229\">We can check our work by multiplying. Use FOIL to confirm that[latex]\\,\\left(x-3\\right)\\left(x+5\\right)={x}^{2}+2x-15.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339328852\" class=\"precalculus qa textbox shaded\">\n<p id=\"fs-id1167339243866\"><strong>Does the order of the factors matter?<\/strong><\/p>\n<p id=\"fs-id1167339243870\"><em>No. Multiplication is commutative, so the order of the factors does not matter.<\/em><\/p>\n<\/div>\n<div id=\"fs-id1167339261843\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_02\">\n<div id=\"fs-id1167339155364\">\n<p id=\"fs-id1167339155365\">Factor[latex]\\,{x}^{2}-7x+6.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339429921\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339429922\">[latex]\\left(x-6\\right)\\left(x-1\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339220936\" class=\"bc-section section\">\n<h3>Factoring by Grouping<\/h3>\n<p id=\"fs-id1167339328929\">Trinomials with leading coefficients other than 1 are slightly more complicated to factor. For these trinomials, we can factor by grouping by dividing the <em>x<\/em> term into the sum of two terms, factoring each portion of the expression separately, and then factoring out the GCF of the entire expression. The trinomial[latex]\\,2{x}^{2}+5x+3\\,[\/latex]can be rewritten as[latex]\\,\\left(2x+3\\right)\\left(x+1\\right)\\,[\/latex]using this process. We begin by rewriting the original expression as[latex]\\,2{x}^{2}+2x+3x+3\\,[\/latex]and then factor each portion of the expression to obtain[latex]\\,2x\\left(x+1\\right)+3\\left(x+1\\right).\\,[\/latex]We then pull out the GCF of[latex]\\,\\left(x+1\\right)\\,[\/latex]to find the factored expression.<\/p>\n<div id=\"fs-id1167339324878\" class=\"textbox key-takeaways\">\n<h3>Factor by Grouping<\/h3>\n<p id=\"fs-id1167339218884\">To factor a trinomial in the form[latex]\\,a{x}^{2}+bx+c\\,[\/latex]by grouping, we find two numbers with a product of[latex]\\,ac\\,[\/latex]and a sum of[latex]\\,b.\\,[\/latex]We use these numbers to divide the[latex]\\,x\\,[\/latex]term into the sum of two terms and factor each portion of the expression separately, then factor out the GCF of the entire expression.<\/p>\n<\/div>\n<div id=\"fs-id1167339318193\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p><strong>Given a trinomial in the form[latex]\\,a{x}^{2}+bx+c,[\/latex]factor by grouping.<\/strong><\/p>\n<ol id=\"fs-id1167339197004\" type=\"1\">\n<li>List factors of[latex]\\,ac.[\/latex]<\/li>\n<li>Find[latex]\\,p\\,[\/latex]and[latex]\\,q,[\/latex]a pair of factors of[latex]\\,ac\\,[\/latex]with a sum of[latex]\\,b.[\/latex]<\/li>\n<li>Rewrite the original expression as[latex]\\,a{x}^{2}+px+qx+c.[\/latex]<\/li>\n<li>Pull out the GCF of[latex]\\,a{x}^{2}+px.[\/latex]<\/li>\n<li>Pull out the GCF of[latex]\\,qx+c.[\/latex]<\/li>\n<li>Factor out the GCF of the expression.<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_03\" class=\"textbox examples\">\n<div id=\"fs-id1167339139430\">\n<div id=\"fs-id1167339139433\">\n<h3>Factoring a Trinomial by Grouping<\/h3>\n<p id=\"fs-id1167339260387\">Factor[latex]\\,5{x}^{2}+7x-6\\,[\/latex]by grouping.<\/p>\n<\/div>\n<div id=\"fs-id1167339176878\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339176880\">We have a trinomial with[latex]\\,a=5,b=7,[\/latex]and[latex]\\,c=-6.\\,[\/latex]First, determine[latex]\\,ac=-30.\\,[\/latex]We need to find two numbers with a product of[latex]\\,-30\\,[\/latex]and a sum of[latex]\\,7.\\,[\/latex]In <a class=\"autogenerated-content\" href=\"#Table_01_05_02\">(Figure)<\/a>, we list factors until we find a pair with the desired sum.<\/p>\n<table id=\"Table_01_05_02\" summary=\"A table with 7 rows and 2 columns. The first column is labeled: Factors of -30 while the second is labeled: Sum of Factors. The entries in the first column are: 1, -30; -1, 30; 2, -15; -2, 15; 3, -10; and -3, 10. The entries in the second column are: -29, 29, -13, 13, -7, and 7.\">\n<caption>&nbsp;<\/caption>\n<thead>\n<tr>\n<th>Factors of[latex]\\,-30[\/latex]<\/th>\n<th>Sum of Factors<\/th>\n<\/tr>\n<\/thead>\n<tbody>\n<tr>\n<td>[latex]1,-30[\/latex]<\/td>\n<td>[latex]-29[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-1,30[\/latex]<\/td>\n<td>29<\/td>\n<\/tr>\n<tr>\n<td>[latex]2,-15[\/latex]<\/td>\n<td>[latex]-13[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-2,15[\/latex]<\/td>\n<td>13<\/td>\n<\/tr>\n<tr>\n<td>[latex]3,-10[\/latex]<\/td>\n<td>[latex]-7[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>[latex]-3,10[\/latex]<\/td>\n<td>7<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p id=\"fs-id1167339303369\">So[latex]\\,p=-3\\,[\/latex]and[latex]\\,q=10.[\/latex]<\/p>\n<div id=\"fs-id1167339159132\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{cc}5{x}^{2}-3x+10x-6 \\hfill & \\phantom{\\rule{2em}{0ex}}\\text{Rewrite the original expression as }a{x}^{2}+px+qx+c.\\hfill \\\\ x\\left(5x-3\\right)+2\\left(5x-3\\right)\\hfill & \\phantom{\\rule{2em}{0ex}}\\text{Factor out the GCF of each part}.\\hfill \\\\ \\left(5x-3\\right)\\left(x+2\\right)\\hfill & \\phantom{\\rule{2em}{0ex}}\\text{Factor out the GCF}\\text{\u200b}\\text{ of the expression}.\\hfill \\end{array}[\/latex]<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339324695\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339324700\">We can check our work by multiplying. Use FOIL to confirm that[latex]\\,\\left(5x-3\\right)\\left(x+2\\right)=5{x}^{2}+7x-6.[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138014\" class=\"textbox tryit\">\n<div id=\"ti_01_05_03\">\n<div id=\"fs-id1167339143599\">\n<p id=\"fs-id1167339143600\">Factor a.[latex]\\,2{x}^{2}+9x+9\\,[\/latex]b.[latex]\\,6{x}^{2}+x-1[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339219115\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339281315\">a.[latex]\\,\\left(2x+3\\right)\\left(x+3\\right)\\,[\/latex]b.[latex]\\,\\left(3x-1\\right)\\left(2x+1\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339300231\" class=\"bc-section section\">\n<h3>Factoring a Perfect Square Trinomial<\/h3>\n<p id=\"fs-id1167339300236\">A perfect square trinomial is a trinomial that can be written as the square of a binomial. Recall that when a binomial is squared, the result is the square of the first term added to twice the product of the two terms and the square of the last term.<\/p>\n<div id=\"fs-id1167339433578\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{ccc}\\hfill {a}^{2}+2ab+{b}^{2}& =& {\\left(a+b\\right)}^{2}\\hfill \\\\ & \\text{and}& \\\\ \\hfill {a}^{2}-2ab+{b}^{2}& =& {\\left(a-b\\right)}^{2}\\hfill \\end{array}[\/latex]<\/div>\n<p id=\"fs-id1167339303412\">We can use this equation to factor any perfect square trinomial.<\/p>\n<div id=\"fs-id1167339158176\" class=\"textbox key-takeaways\">\n<h3>Perfect Square Trinomials<\/h3>\n<p id=\"fs-id1167339321523\">A perfect square trinomial can be written as the square of a binomial:<\/p>\n<div id=\"Equation_01_05_01\">[latex]{a}^{2}+2ab+{b}^{2}={\\left(a+b\\right)}^{2}[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1167339168210\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339225968\"><strong>Given a perfect square trinomial, factor it into the square of a binomial.<br \/>\n<\/strong><\/p>\n<ol id=\"fs-id1167339321581\" type=\"1\">\n<li>Confirm that the first and last term are perfect squares.<\/li>\n<li>Confirm that the middle term is twice the product of[latex]\\,ab.[\/latex]<\/li>\n<li>Write the factored form as[latex]\\,{\\left(a+b\\right)}^{2}.[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_04\" class=\"textbox examples\">\n<div id=\"fs-id1167339140179\">\n<div id=\"fs-id1167339140181\">\n<h3>Factoring a Perfect Square Trinomial<\/h3>\n<p id=\"fs-id1167339140186\">Factor[latex]\\,25{x}^{2}+20x+4.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339290269\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339290271\">Notice that[latex]\\,25{x}^{2}\\,[\/latex]and[latex]\\,4\\,[\/latex]are perfect squares because[latex]\\,25{x}^{2}={\\left(5x\\right)}^{2}\\,[\/latex]and[latex]\\,4={2}^{2}.\\,[\/latex]Then check to see if the middle term is twice the product of[latex]\\,5x\\,[\/latex]and[latex]\\,2.\\,[\/latex]The middle term is, indeed, twice the product:[latex]\\,2\\left(5x\\right)\\left(2\\right)=20x.\\,[\/latex]Therefore, the trinomial is a perfect square trinomial and can be written as[latex]\\,{\\left(5x+2\\right)}^{2}.[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339212449\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_04\">\n<div id=\"fs-id1167339145226\">\n<p id=\"fs-id1167339145228\">Factor[latex]\\,49{x}^{2}-14x+1.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339220792\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339220793\">[latex]{\\left(7x-1\\right)}^{2}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344862\" class=\"bc-section section\">\n<h3>Factoring a Difference of Squares<\/h3>\n<p id=\"fs-id1167339344867\">A difference of squares is a perfect square subtracted from a perfect square. Recall that a difference of squares can be rewritten as factors containing the same terms but opposite signs because the middle terms cancel each other out when the two factors are multiplied.<\/p>\n<div id=\"fs-id1167339184434\" class=\"unnumbered aligncenter\">[latex]{a}^{2}-{b}^{2}=\\left(a+b\\right)\\left(a-b\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339139364\">We can use this equation to factor any differences of squares.<\/p>\n<div id=\"fs-id1167339139367\" class=\"textbox key-takeaways\">\n<h3>Differences of Squares<\/h3>\n<p id=\"fs-id1167339212514\">A difference of squares can be rewritten as two factors containing the same terms but opposite signs.<\/p>\n<div id=\"Equation_01_05_02\">[latex]{a}^{2}-{b}^{2}=\\left(a+b\\right)\\left(a-b\\right)[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1167339243070\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339243077\"><strong>Given a difference of squares, factor it into binomials.<\/strong><\/p>\n<ol id=\"fs-id1167339259636\" type=\"1\">\n<li>Confirm that the first and last term are perfect squares.<\/li>\n<li>Write the factored form as[latex]\\,\\left(a+b\\right)\\left(a-b\\right).[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_05\" class=\"textbox examples\">\n<div id=\"fs-id1167339296405\">\n<div id=\"fs-id1167339296407\">\n<h3>Factoring a Difference of Squares<\/h3>\n<p id=\"fs-id1167339296412\">Factor[latex]\\,9{x}^{2}-25.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339296378\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339432877\">Notice that[latex]\\,9{x}^{2}\\,[\/latex]and[latex]\\,25\\,[\/latex]are perfect squares because[latex]\\,9{x}^{2}={\\left(3x\\right)}^{2}\\,[\/latex]and[latex]\\,25={5}^{2}.\\,[\/latex]The polynomial represents a difference of squares and can be rewritten as[latex]\\,\\left(3x+5\\right)\\left(3x-5\\right).[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339432780\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_05\">\n<div id=\"fs-id1167339324582\">\n<p id=\"fs-id1167339324583\">Factor[latex]\\,81{y}^{2}-100.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339262683\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339262684\">[latex]\\left(9y+10\\right)\\left(9y-10\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339240123\" class=\"precalculus qa textbox shaded\">\n<p id=\"fs-id1167339240130\"><strong>Is there a formula to factor the sum of squares?<\/strong><\/p>\n<p id=\"fs-id1167339240135\"><em>No. A sum of squares cannot be factored.<\/em><\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339281638\" class=\"bc-section section\">\n<h3>Factoring the Sum and Difference of Cubes<\/h3>\n<p id=\"fs-id1167339281643\">Now, we will look at two new special products: the sum and difference of cubes. Although the sum of squares cannot be factored, the sum of cubes can be factored into a binomial and a trinomial.<\/p>\n<div id=\"fs-id1167339281648\" class=\"unnumbered aligncenter\">[latex]{a}^{3}+{b}^{3}=\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339281668\">Similarly, the sum of cubes can be factored into a binomial and a trinomial, but with different signs.<\/p>\n<div id=\"fs-id1167339281486\" class=\"unnumbered aligncenter\">[latex]{a}^{3}-{b}^{3}=\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339281447\">We can use the acronym SOAP to remember the signs when factoring the sum or difference of cubes. The first letter of each word relates to the signs: <strong>S<\/strong>ame <strong>O<\/strong>pposite <strong>A<\/strong>lways <strong>P<\/strong>ositive. For example, consider the following example.<\/p>\n<div id=\"fs-id1167339281464\" class=\"unnumbered aligncenter\">[latex]{x}^{3}-{2}^{3}=\\left(x-2\\right)\\left({x}^{2}+2x+4\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339280881\">The sign of the first 2 is the <em>same<\/em> as the sign between[latex]\\,{x}^{3}-{2}^{3}.\\,[\/latex]The sign of the[latex]\\,2x\\,[\/latex]term is <em>opposite<\/em> the sign between[latex]\\,{x}^{3}-{2}^{3}.\\,[\/latex]And the sign of the last term, 4, is <em>always positive<\/em>.<\/p>\n<div id=\"fs-id1167339281550\" class=\"textbox key-takeaways\">\n<h3>Sum and Difference of Cubes<\/h3>\n<p id=\"fs-id1167339281559\">We can factor the sum of two cubes as<\/p>\n<div id=\"Equation_01_05_03\">[latex]{a}^{3}+{b}^{3}=\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right)[\/latex]<\/div>\n<p id=\"fs-id1167339281287\">We can factor the difference of two cubes as<\/p>\n<div id=\"Equation_01_05_04\">[latex]{a}^{3}-{b}^{3}=\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right)[\/latex]<\/div>\n<\/div>\n<div id=\"fs-id1167339324784\" class=\"precalculus howto textbox tryit\">\n<h3>How To<\/h3>\n<p id=\"fs-id1167339324792\"><strong>Given a sum of cubes or difference of cubes, factor it.<\/strong><\/p>\n<ol id=\"fs-id1167339324796\" type=\"1\">\n<li>Confirm that the first and last term are cubes,[latex]\\,{a}^{3}+{b}^{3}\\,[\/latex]or[latex]\\,{a}^{3}-{b}^{3}.[\/latex]<\/li>\n<li>For a sum of cubes, write the factored form as[latex]\\,\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right).\\,[\/latex]For a difference of cubes, write the factored form as[latex]\\,\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right).[\/latex]<\/li>\n<\/ol>\n<\/div>\n<div id=\"Example_01_05_06\" class=\"textbox examples\">\n<div id=\"fs-id1167339240349\">\n<div id=\"fs-id1167339240351\">\n<h3>Factoring a Sum of Cubes<\/h3>\n<p id=\"fs-id1167339240357\">Factor[latex]\\,{x}^{3}+512.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339324945\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p>Notice that[latex]\\,{x}^{3}\\,[\/latex]and[latex]\\,512\\,[\/latex]are cubes because[latex]\\,{8}^{3}=512.\\,[\/latex]Rewrite the sum of cubes as[latex]\\,\\left(x+8\\right)\\left({x}^{2}-8x+64\\right).[\/latex]<\/details>\n<\/div>\n<div id=\"fs-id1167339230837\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339230842\">After writing the sum of cubes this way, we might think we should check to see if the trinomial portion can be factored further. However, the trinomial portion cannot be factored, so we do not need to check.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339243153\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_06\">\n<div id=\"fs-id1167339243165\">\n<p id=\"fs-id1167339243166\">Factor the sum of cubes:[latex]\\,216{a}^{3}+{b}^{3}.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339296456\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339296457\">[latex]\\left(6a+b\\right)\\left(36{a}^{2}-6ab+{b}^{2}\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"Example_01_05_07\" class=\"textbox examples\">\n<div id=\"fs-id1167339281618\">\n<div id=\"fs-id1167339281620\">\n<h3>Factoring a Difference of Cubes<\/h3>\n<p id=\"fs-id1167339281626\">Factor[latex]\\,8{x}^{3}-125.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339262635\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p>Notice that[latex]\\,8{x}^{3}\\,[\/latex]and[latex]\\,125\\,[\/latex]are cubes because[latex]\\,8{x}^{3}={\\left(2x\\right)}^{3}\\,[\/latex]and[latex]\\,125={5}^{3}.\\,[\/latex]Write the difference of cubes as[latex]\\,\\left(2x-5\\right)\\left(4{x}^{2}+10x+25\\right).[\/latex]<\/details>\n<\/div>\n<div id=\"fs-id1167339223214\">\n<h4>Analysis<\/h4>\n<p id=\"fs-id1167339223219\">Just as with the sum of cubes, we will not be able to further factor the trinomial portion.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339259671\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_07\">\n<div id=\"fs-id1167339259683\">\n<p id=\"fs-id1167339259684\">Factor the difference of cubes:[latex]\\,1,000{x}^{3}-1.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339259713\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339259714\">[latex]\\left(10x-1\\right)\\left(100{x}^{2}+10x+1\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339432601\" class=\"bc-section section\">\n<h3>Factoring Expressions with Fractional or Negative Exponents<\/h3>\n<p id=\"fs-id1167339432607\">Expressions with fractional or negative exponents can be factored by pulling out a GCF. Look for the variable or exponent that is common to each term of the expression and pull out that variable or exponent raised to the lowest power. These expressions follow the same factoring rules as those with integer exponents. For instance,[latex]\\,2{x}^{\\frac{1}{4}}+5{x}^{\\frac{3}{4}}\\,[\/latex]can be factored by pulling out[latex]\\,{x}^{\\frac{1}{4}}\\,[\/latex]and being rewritten as[latex]\\,{x}^{\\frac{1}{4}}\\left(2+5{x}^{\\frac{1}{2}}\\right).[\/latex]<\/p>\n<div id=\"Example_01_05_08\" class=\"textbox examples\">\n<div id=\"fs-id1167339196684\">\n<div id=\"fs-id1167339196686\">\n<h3>Factoring an Expression with Fractional or Negative Exponents<\/h3>\n<p id=\"fs-id1167339196691\">Factor[latex]\\,3x{\\left(x+2\\right)}^{\\frac{-1}{3}}+4{\\left(x+2\\right)}^{\\frac{2}{3}}.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339230930\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339230932\">Factor out the term with the lowest value of the exponent. In this case, that would be[latex]\\,{\\left(x+2\\right)}^{-\\frac{1}{3}}.[\/latex]<\/p>\n<div id=\"fs-id1167339230987\" class=\"unnumbered aligncenter\">[latex]\\begin{array}{cc}{\\left(x+2\\right)}^{-\\frac{1}{3}}\\left(3x+4\\left(x+2\\right)\\right)\\hfill & \\phantom{\\rule{2em}{0ex}}\\text{Factor out the GCF}.\\hfill \\\\ {\\left(x+2\\right)}^{-\\frac{1}{3}}\\left(3x+4x+8\\right)\\hfill & \\phantom{\\rule{2em}{0ex}}\\text{Simplify}.\\hfill \\\\ {\\left(x+2\\right)}^{-\\frac{1}{3}}\\left(7x+8\\right)\\hfill & \\end{array}[\/latex]<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339309570\" class=\"textbox tryit\">\n<h3>Try It<\/h3>\n<div id=\"ti_01_05_08\">\n<div id=\"fs-id1167339309581\">\n<p id=\"fs-id1167339309582\">Factor[latex]\\,2{\\left(5a-1\\right)}^{\\frac{3}{4}}+7a{\\left(5a-1\\right)}^{-\\frac{1}{4}}.[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339273714\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339273715\">[latex]{\\left(5a-1\\right)}^{-\\frac{1}{4}}\\left(17a-2\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339306561\" class=\"precalculus media\">\n<p id=\"fs-id1167339306568\">Access these online resources for additional instruction and practice with factoring polynomials.<\/p>\n<ul id=\"fs-id1167339306573\">\n<li><a href=\"http:\/\/openstaxcollege.org\/l\/findgcftofact\">Identify GCF<\/a><\/li>\n<li><a href=\"http:\/\/openstaxcollege.org\/l\/facttrinom1\">Factor Trinomials when a Equals 1<\/a><\/li>\n<li><a href=\"http:\/\/openstaxcollege.org\/l\/facttrinom2\">Factor Trinomials when a is not equal to 1<\/a><\/li>\n<li><a href=\"http:\/\/openstaxcollege.org\/l\/sumdifcube\">Factor Sum or Difference of Cubes<\/a><\/li>\n<\/ul>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339306605\" class=\"key-equations\">\n<h3>Key Equations<\/h3>\n<table id=\"fs-id1167339306612\" summary=\"..\">\n<tbody>\n<tr>\n<td>difference of squares<\/td>\n<td>[latex]{a}^{2}-{b}^{2}=\\left(a+b\\right)\\left(a-b\\right)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>perfect square trinomial<\/td>\n<td>[latex]{a}^{2}+2ab+{b}^{2}={\\left(a+b\\right)}^{2}[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>sum of cubes<\/td>\n<td>[latex]{a}^{3}+{b}^{3}=\\left(a+b\\right)\\left({a}^{2}-ab+{b}^{2}\\right)[\/latex]<\/td>\n<\/tr>\n<tr>\n<td>difference of cubes<\/td>\n<td>[latex]{a}^{3}-{b}^{3}=\\left(a-b\\right)\\left({a}^{2}+ab+{b}^{2}\\right)[\/latex]<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<\/div>\n<div id=\"fs-id1167339199496\" class=\"textbox key-takeaways\">\n<ul id=\"fs-id1167339199500\">\n<li>The greatest common factor, or GCF, can be factored out of a polynomial. Checking for a GCF should be the first step in any factoring problem. See <a class=\"autogenerated-content\" href=\"#Example_01_05_01\">(Figure)<\/a>.<\/li>\n<li>Trinomials with leading coefficient 1 can be factored by finding numbers that have a product of the third term and a sum of the second term. See <a class=\"autogenerated-content\" href=\"#Example_01_05_02\">(Figure)<\/a>.<\/li>\n<li>Trinomials can be factored using a process called factoring by grouping. See <a class=\"autogenerated-content\" href=\"#Example_01_05_03\">(Figure)<\/a>.<\/li>\n<li>Perfect square trinomials and the difference of squares are special products and can be factored using equations. See <a class=\"autogenerated-content\" href=\"#Example_01_05_04\">(Figure)<\/a> and <a class=\"autogenerated-content\" href=\"#Example_01_05_05\">(Figure)<\/a>.<\/li>\n<li>The sum of cubes and the difference of cubes can be factored using equations. See <a class=\"autogenerated-content\" href=\"#Example_01_05_06\">(Figure)<\/a> and <a class=\"autogenerated-content\" href=\"#Example_01_05_07\">(Figure)<\/a>.<\/li>\n<li>Polynomials containing fractional and negative exponents can be factored by pulling out a GCF. See <a class=\"autogenerated-content\" href=\"#Example_01_05_08\">(Figure)<\/a>.<\/li>\n<\/ul>\n<\/div>\n<div id=\"fs-id1167339220212\" class=\"textbox exercises\">\n<div id=\"fs-id1167339220216\" class=\"bc-section section\">\n<h4>Verbal<\/h4>\n<div id=\"fs-id1167339220221\">\n<div id=\"fs-id1167339220222\">\n<p id=\"fs-id1167339220223\">If the terms of a polynomial do not have a GCF, does that mean it is not factorable? Explain.<\/p>\n<\/div>\n<div id=\"fs-id1167339220227\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339220228\">The terms of a polynomial do not have to have a common factor for the entire polynomial to be factorable. For example,[latex]\\,4{x}^{2}\\,[\/latex]and[latex]\\,-9{y}^{2}\\,[\/latex]don\u2019t have a common factor, but the whole polynomial is still factorable:[latex]\\,4{x}^{2}-9{y}^{2}=\\left(2x+3y\\right)\\left(2x-3y\\right).[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226305\">\n<div id=\"fs-id1167339226306\">\n<p id=\"fs-id1167339226307\">A polynomial is factorable, but it is not a perfect square trinomial or a difference of two squares. Can you factor the polynomial without finding the GCF?<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226312\">\n<div id=\"fs-id1167339226313\">\n<p id=\"fs-id1167339226314\">How do you factor by grouping?<\/p>\n<\/div>\n<div id=\"fs-id1167339226317\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339226318\">Divide the[latex]\\,x\\,[\/latex]term into the sum of two terms, factor each portion of the expression separately, and then factor out the GCF of the entire expression.<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226337\" class=\"bc-section section\">\n<h4>Algebraic<\/h4>\n<p id=\"fs-id1167339226343\">For the following exercises, find the greatest common factor.<\/p>\n<div id=\"fs-id1167339226346\">\n<div id=\"fs-id1167339226347\">\n<p id=\"fs-id1167339226348\">[latex]14x+4xy-18x{y}^{2}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339226385\">\n<div id=\"fs-id1167339226386\">\n<p id=\"fs-id1167339226388\">[latex]49m{b}^{2}-35{m}^{2}ba+77m{a}^{2}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339218641\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339218642\">[latex]7m[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339218656\">\n<div id=\"fs-id1167339218657\">\n<p id=\"fs-id1167339218658\">[latex]30{x}^{3}y-45{x}^{2}{y}^{2}+135x{y}^{3}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339218720\">\n<div id=\"fs-id1167339218721\">\n<p id=\"fs-id1167339218722\">[latex]200{p}^{3}{m}^{3}-30{p}^{2}{m}^{3}+40{m}^{3}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339426591\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339426592\">[latex]10{m}^{3}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339426613\">\n<div id=\"fs-id1167339426614\">\n<p id=\"fs-id1167339426615\">[latex]36{j}^{4}{k}^{2}-18{j}^{3}{k}^{3}+54{j}^{2}{k}^{4}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339426694\">\n<div id=\"fs-id1167339426695\">\n<p id=\"fs-id1167339426696\">[latex]6{y}^{4}-2{y}^{3}+3{y}^{2}-y[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339196474\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339196475\">[latex]y[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<p id=\"fs-id1167339196483\">For the following exercises, factor by grouping.<\/p>\n<div id=\"fs-id1167339196486\">\n<div id=\"fs-id1167339196488\">\n<p id=\"fs-id1167339196489\">[latex]6{x}^{2}+5x-4[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339196521\">\n<div id=\"fs-id1167339196522\">\n<p id=\"fs-id1167339196523\">[latex]2{a}^{2}+9a-18[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339196555\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339196556\">[latex]\\left(2a-3\\right)\\left(a+6\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339260424\">\n<div id=\"fs-id1167339260425\">\n<p id=\"fs-id1167339260426\">[latex]6{c}^{2}+41c+63[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339260458\">\n<div id=\"fs-id1167339260459\">\n<p id=\"fs-id1167339260460\">[latex]6{n}^{2}-19n-11[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339260492\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339260493\">[latex]\\left(3n-11\\right)\\left(2n+1\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339260541\">\n<div id=\"fs-id1167339260542\">\n<p id=\"fs-id1167339260543\">[latex]20{w}^{2}-47w+24[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339303598\">\n<div id=\"fs-id1167339303599\">\n<p id=\"fs-id1167339303600\">[latex]2{p}^{2}-5p-7[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339303632\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339303633\">[latex]\\left(p+1\\right)\\left(2p-7\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<p id=\"fs-id1167339303679\">For the following exercises, factor the polynomial.<\/p>\n<div id=\"fs-id1167339303682\">\n<div id=\"fs-id1167339303683\">\n<p id=\"fs-id1167339303684\">[latex]7{x}^{2}+48x-7[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339303716\">\n<div id=\"fs-id1167339303717\">\n<p id=\"fs-id1167339303718\">[latex]10{h}^{2}-9h-9[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339239045\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339239046\">[latex]\\left(5h+3\\right)\\left(2h-3\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239094\">\n<div id=\"fs-id1167339239095\">\n<p id=\"fs-id1167339239096\">[latex]2{b}^{2}-25b-247[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239128\">\n<div id=\"fs-id1167339239129\">\n<p id=\"fs-id1167339239130\">[latex]9{d}^{2}-73d+8[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339239162\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339239163\">[latex]\\left(9d-1\\right)\\left(d-8\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339321370\">\n<div id=\"fs-id1167339321372\">\n<p id=\"fs-id1167339321373\">[latex]90{v}^{2}-181v+90[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339321405\">\n<div id=\"fs-id1167339321406\">\n<p id=\"fs-id1167339321407\">[latex]12{t}^{2}+t-13[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339321437\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339321438\">[latex]\\left(12t+13\\right)\\left(t-1\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339321484\">\n<div id=\"fs-id1167339321485\">\n<p id=\"fs-id1167339321486\">[latex]2{n}^{2}-n-15[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344423\">\n<div id=\"fs-id1167339344424\">\n<p id=\"fs-id1167339344426\">[latex]16{x}^{2}-100[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339344451\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p>[latex]\\left(4x+10\\right)\\left(4x-10\\right)[\/latex]<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344500\">\n<div id=\"fs-id1167339344501\">\n<p id=\"fs-id1167339344502\">[latex]25{y}^{2}-196[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339344528\">\n<div id=\"fs-id1167339344529\">\n<p id=\"fs-id1167339344530\">[latex]121{p}^{2}-169[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339344556\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339344557\">[latex]\\left(11p+13\\right)\\left(11p-13\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138818\">\n<div id=\"fs-id1167339138819\">\n<p id=\"fs-id1167339138820\">[latex]4{m}^{2}-9[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138845\">\n<div id=\"fs-id1167339138846\">\n<p id=\"fs-id1167339138848\">[latex]361{d}^{2}-81[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339138873\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339138874\">[latex]\\left(19d+9\\right)\\left(19d-9\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339138922\">\n<div id=\"fs-id1167339138923\">\n<p id=\"fs-id1167339138924\">[latex]324{x}^{2}-121[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339273782\">\n<div id=\"fs-id1167339273783\">\n<p id=\"fs-id1167339273784\">[latex]144{b}^{2}-25{c}^{2}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339273818\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339273819\">[latex]\\left(12b+5c\\right)\\left(12b-5c\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339273871\">\n<div id=\"fs-id1167339273872\">\n<p id=\"fs-id1167339273873\">[latex]16{a}^{2}-8a+1[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339273905\">\n<div id=\"fs-id1167339273906\">\n<p id=\"fs-id1167339273907\">[latex]49{n}^{2}+168n+144[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339227654\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339227655\">[latex]{\\left(7n+12\\right)}^{2}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339227694\">\n<div id=\"fs-id1167339227695\">\n<p id=\"fs-id1167339227696\">[latex]121{x}^{2}-88x+16[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339227728\">\n<div id=\"fs-id1167339227729\">\n<p id=\"fs-id1167339227730\">[latex]225{y}^{2}+120y+16[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339227762\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339227763\">[latex]{\\left(15y+4\\right)}^{2}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339227802\">\n<div id=\"fs-id1167339227803\">\n<p id=\"fs-id1167339227804\">[latex]{m}^{2}-20m+100[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339213934\">\n<div id=\"fs-id1167339213935\">\n<p id=\"fs-id1167339213936\">[latex]25{p}^{2}-120m+144[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339213968\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339213969\">[latex]{\\left(5p-12\\right)}^{2}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339214008\">\n<div id=\"fs-id1167339214009\">\n<p id=\"fs-id1167339214010\">[latex]36{q}^{2}+60q+25[\/latex]<\/p>\n<\/div>\n<\/div>\n<p id=\"fs-id1167339214042\">For the following exercises, factor the polynomials.<\/p>\n<div>\n<div>\n<p id=\"fs-id1167339214047\">[latex]{x}^{3}+216[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339214070\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339214072\">[latex]\\left(x+6\\right)\\left({x}^{2}-6x+36\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339222855\">\n<div id=\"fs-id1167339222856\">\n<p id=\"fs-id1167339222857\">[latex]27{y}^{3}-8[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339222883\">\n<div id=\"fs-id1167339222884\">\n<p id=\"fs-id1167339222885\">[latex]125{a}^{3}+343[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339222911\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339222912\">[latex]\\left(5a+7\\right)\\left(25{a}^{2}-35a+49\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339222974\">\n<div id=\"fs-id1167339222975\">\n<p id=\"fs-id1167339222976\">[latex]{b}^{3}-8{d}^{3}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339223008\">\n<div id=\"fs-id1167339223009\">\n<p id=\"fs-id1167339223010\">[latex]64{x}^{3}-125[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339223036\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339223037\">[latex]\\left(4x-5\\right)\\left(16{x}^{2}+20x+25\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339280936\">\n<div id=\"fs-id1167339280937\">\n<p id=\"fs-id1167339280938\">[latex]729{q}^{3}+1331[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339280964\">\n<div id=\"fs-id1167339280965\">\n<p id=\"fs-id1167339280966\">[latex]125{r}^{3}+1,728{s}^{3}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339281004\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339281006\">[latex]\\left(5r+12s\\right)\\left(25{r}^{2}-60rs+144{s}^{2}\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339281080\">\n<div id=\"fs-id1167339281081\">\n<p id=\"fs-id1167339281082\">[latex]4x{\\left(x-1\\right)}^{-\\frac{2}{3}}+3{\\left(x-1\\right)}^{\\frac{1}{3}}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339225624\">\n<div id=\"fs-id1167339225626\">\n<p id=\"fs-id1167339225627\">[latex]3c{\\left(2c+3\\right)}^{-\\frac{1}{4}}-5{\\left(2c+3\\right)}^{\\frac{3}{4}}[\/latex]<\/p>\n<\/div>\n<div>\n<div class=\"textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339225726\">[latex]{\\left(2c+3\\right)}^{-\\frac{1}{4}}\\left(-7c-15\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339225798\">\n<div id=\"fs-id1167339317629\">\n<p id=\"fs-id1167339317630\">[latex]3t{\\left(10t+3\\right)}^{\\frac{1}{3}}+7{\\left(10t+3\\right)}^{\\frac{4}{3}}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339317726\">\n<div id=\"fs-id1167339317727\">\n<p id=\"fs-id1167339317728\">[latex]14x{\\left(x+2\\right)}^{-\\frac{2}{5}}+5{\\left(x+2\\right)}^{\\frac{3}{5}}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339317822\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339317823\">[latex]{\\left(x+2\\right)}^{-\\frac{2}{5}}\\left(19x+10\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339437841\">\n<div id=\"fs-id1167339437842\">\n<p id=\"fs-id1167339437843\">[latex]9y{\\left(3y-13\\right)}^{\\frac{1}{5}}-2{\\left(3y-13\\right)}^{\\frac{6}{5}}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339437939\">\n<div>\n<p id=\"fs-id1167339437941\">[latex]5z{\\left(2z-9\\right)}^{-\\frac{3}{2}}+11{\\left(2z-9\\right)}^{-\\frac{1}{2}}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339438041\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339438042\">[latex]{\\left(2z-9\\right)}^{-\\frac{3}{2}}\\left(27z-99\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339315699\">\n<div id=\"fs-id1167339315700\">\n<p id=\"fs-id1167339315701\">[latex]6d{\\left(2d+3\\right)}^{-\\frac{1}{6}}+5{\\left(2d+3\\right)}^{\\frac{5}{6}}[\/latex]<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339315800\" class=\"bc-section section\">\n<h4>Real-World Applications<\/h4>\n<p id=\"fs-id1167339315805\">For the following exercises, consider this scenario:<\/p>\n<p id=\"fs-id1167339315809\">Charlotte has appointed a chairperson to lead a city beautification project. The first act is to install statues and fountains in one of the city\u2019s parks. The park is a rectangle with an area of[latex]\\,98{x}^{2}+105x-27\\,[\/latex]m<sup>2<\/sup>, as shown in the figure below. The length and width of the park are perfect factors of the area.<\/p>\n<p><span id=\"fs-id1167339315854\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3252\/2018\/07\/19132158\/CNX_CAT_Figure_01_05_201.jpg\" alt=\"A rectangle that\u2019s textured to look like a field. The field is labeled: l times w = ninety-eight times x squared plus one hundred five times x minus twenty-seven.\" \/><\/span><\/p>\n<div id=\"fs-id1167339315866\">\n<div id=\"fs-id1167339315867\">\n<p id=\"fs-id1167339315868\">Factor by grouping to find the length and width of the park.<\/p>\n<\/div>\n<div id=\"fs-id1167339315871\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339315872\">[latex]\\left(14x-3\\right)\\left(7x+9\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239178\">\n<div id=\"fs-id1167339239179\">\n<p id=\"fs-id1167339239180\">A statue is to be placed in the center of the park. The area of the base of the statue is[latex]\\,4{x}^{2}+12x+9{\\text{m}}^{2}.\\,[\/latex]Factor the area to find the lengths of the sides of the statue.<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239218\">\n<div id=\"fs-id1167339239219\">\n<p id=\"fs-id1167339239220\">At the northwest corner of the park, the city is going to install a fountain. The area of the base of the fountain is[latex]\\,9{x}^{2}-25{\\text{m}}^{2}.\\,[\/latex]Factor the area to find the lengths of the sides of the fountain.<\/p>\n<\/div>\n<div id=\"fs-id1167339239252\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339239254\">[latex]\\left(3x+5\\right)\\left(3x-5\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<p id=\"fs-id1167339239302\">For the following exercise, consider the following scenario:<\/p>\n<p id=\"fs-id1167339239305\">A school is installing a flagpole in the central plaza. The plaza is a square with side length 100 yd. as shown in the figure below. The flagpole will take up a square plot with area[latex]\\,{x}^{2}-6x+9[\/latex]yd<sup>2<\/sup>.<\/p>\n<p><span id=\"fs-id1167339239346\"><img decoding=\"async\" src=\"https:\/\/s3-us-west-2.amazonaws.com\/courses-images\/wp-content\/uploads\/sites\/3252\/2018\/07\/19132200\/CNX_CAT_Figure_01_05_202.jpg\" alt=\"A square that\u2019s textured to look like a field with a missing piece in the shape of a square in the center. The sides of the larger square are labeled: 100 yards. The center square is labeled: Area: x squared minus six times x plus nine.\" \/><\/span><\/p>\n<div id=\"fs-id1167339239356\">\n<div id=\"fs-id1167339239358\">\n<p id=\"fs-id1167339239359\">Find the length of the base of the flagpole by factoring.<\/p>\n<\/div>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339239363\" class=\"bc-section section\">\n<h4>Extensions<\/h4>\n<p id=\"fs-id1167339239368\">For the following exercises, factor the polynomials completely.<\/p>\n<div id=\"fs-id1167339239371\">\n<div id=\"fs-id1167339239372\">\n<p id=\"fs-id1167339239374\">[latex]16{x}^{4}-200{x}^{2}+625[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339239413\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339239414\">[latex]{\\left(2x+5\\right)}^{2}{\\left(2x-5\\right)}^{2}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339240884\">\n<div id=\"fs-id1167339240886\">\n<p id=\"fs-id1167339240887\">[latex]81{y}^{4}-256[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339240912\">\n<div id=\"fs-id1167339240913\">\n<p id=\"fs-id1167339240914\">[latex]16{z}^{4}-2,401{a}^{4}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339240953\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339240954\">[latex]\\left(4{z}^{2}+49{a}^{2}\\right)\\left(2z+7a\\right)\\left(2z-7a\\right)[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339241043\">\n<div id=\"fs-id1167339241044\">\n<p id=\"fs-id1167339241045\">[latex]5x{\\left(3x+2\\right)}^{-\\frac{2}{4}}+{\\left(12x+8\\right)}^{\\frac{3}{2}}[\/latex]<\/p>\n<\/div>\n<\/div>\n<div id=\"fs-id1167339433017\">\n<div id=\"fs-id1167339433018\">\n<p id=\"fs-id1167339433019\">[latex]{\\left(32{x}^{3}+48{x}^{2}-162x-243\\right)}^{-1}[\/latex]<\/p>\n<\/div>\n<div id=\"fs-id1167339433090\" class=\"solution textbox shaded\">\n<details>\n<summary>Show Solution<\/summary>\n<p id=\"fs-id1167339433091\">[latex]\\frac{1}{\\left(4x+9\\right)\\left(4x-9\\right)\\left(2x+3\\right)}[\/latex]<\/p>\n<\/details>\n<\/div>\n<\/div>\n<\/div>\n<\/div>\n<div class=\"textbox shaded\">\n<h3>Glossary<\/h3>\n<dl id=\"fs-id1167339433176\">\n<dt>factor by grouping<\/dt>\n<dd id=\"fs-id1167339433179\">a method for factoring a trinomial in the form[latex]\\,a{x}^{2}+bx+c\\,[\/latex]by dividing the <em>x<\/em> term into the sum of two terms, factoring each portion of the expression separately, and then factoring out the GCF of the entire expression<\/dd>\n<\/dl>\n<dl id=\"fs-id1167339433223\">\n<dt>greatest common factor<\/dt>\n<dd id=\"fs-id1167339433226\">the largest polynomial that divides evenly into each polynomial<\/dd>\n<\/dl>\n<\/div>\n","protected":false},"author":291,"menu_order":6,"template":"","meta":{"pb_show_title":null,"pb_short_title":"","pb_subtitle":"","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-29","chapter","type-chapter","status-publish","hentry"],"part":18,"_links":{"self":[{"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/chapters\/29","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/wp\/v2\/users\/291"}],"version-history":[{"count":1,"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/chapters\/29\/revisions"}],"predecessor-version":[{"id":30,"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/chapters\/29\/revisions\/30"}],"part":[{"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/parts\/18"}],"metadata":[{"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/chapters\/29\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/wp\/v2\/media?parent=29"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/pressbooks\/v2\/chapter-type?post=29"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/wp\/v2\/contributor?post=29"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/integrations.pressbooks.network\/testinternalcloneforcomparison\/wp-json\/wp\/v2\/license?post=29"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}